相关疑难解决方法(0)

我正在尝试以编程方式构建UI.如何让这个动作起作用？我正在与Swift一起开发.

viewDidLoad中的代码:

override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view, typically from a nib.
        let myFirstLabel = UILabel()
        let myFirstButton = UIButton()
        myFirstLabel.text = "I made a label on the screen #toogood4you"
        myFirstLabel.font = UIFont(name: "MarkerFelt-Thin", size: 45)
        myFirstLabel.textColor = UIColor.redColor()
        myFirstLabel.textAlignment = .Center
        myFirstLabel.numberOfLines = 5
        myFirstLabel.frame = CGRectMake(15, 54, 300, 500)
        myFirstButton.setTitle("?", forState: .Normal)
        myFirstButton.setTitleColor(UIColor.blueColor(), forState: .Normal)
        myFirstButton.frame = CGRectMake(15, -50, 300, 500)
        myFirstButton.addTarget(self, action: "pressed", forControlEvents: .TouchUpInside)
        self.view.addSubview(myFirstLabel)
        self.view.addSubview(myFirstButton)
    }

        func …

我想做一个圆形的拇指和拇指按下按钮.

我应该使用ImageView还是Button作为超类？

我如何在Swift中执行此操作？

我看到一些示例代码将相同的OnClick事件分配给Android中的所有按钮(即使它们执行完全不同的操作).如何用Swift做到这一点

Android示例:

@Override 
public void onCreate(Bundle savedInstanceState) {
        button1.setOnClickListener(onClickListener);
        button2.setOnClickListener(onClickListener);
        button3.setOnClickListener(onClickListener);
} 

private OnClickListener onClickListener = new OnClickListener() {
     @Override 
     public void onClick(View v) {
         switch(v.getId()){
             case R.id.button1:
                  //DO something 
             break; 
             case R.id.button2:
                  //DO something 
             break; 
             case R.id.button3:
                  //DO something 
             break; 
         } 

   } 
}; 

注意:我不想以编程方式创建按钮.

如何以编程方式向按钮添加操作.我需要在mapView中为按钮添加show动作.谢谢

let button = UIButton(type: UIButtonType.Custom) as UIButton

从如何以编程方式创建按钮？

自我在快速游乐场不起作用:

button.addTarget(self, action: "buttonAction:", forControlEvents: UIControlEvents.TouchUpInside)

错误:

游乐场执行失败:错误:: 42:13:错误:使用未解析的标识符'self'

我也尝试用里面的buttonAction方法创建一个类,但是当我点击按钮时,没有任何东西在控制台中打印

import UIKit

class myself {


    func buttonAction(sender:UIButton!)
    {
        println("Button tapped")
    }

}

var s = myself()

// Create View
var f = CGRect(x:0,y:0,width:200,height:200)
var view = UIView(frame:f)


// Create Button
var b = UIButton(frame: f)
b.setTitle("Hello", forState: UIControlState.Normal)
b.addTarget(s, action: "buttonAction:", forControlEvents: UIControlEvents.TouchUpInside)

view.addSubview(b)

view

我有一个包含 3 页的页面视图控制器。我希望在所有这些按钮之上都可以看到一个“浮动”按钮。我曾尝试为 PageView 使用容器视图，但这似乎不起作用。我还能如何让按钮在所有 3 个页面中保持可见？

我已尝试使用此问题中所述的容器视图： UIButton 跨 UIPageViewController 的所有页面

我创建了一个按钮，但由于某种原因，触摸无法识别：

override func viewDidLoad() {
        super.viewDidLoad()

        var settingsButton = UIButton.buttonWithType(UIButtonType.System) as UIButton
        settingsButton.frame = CGRectMake(self.view.frame.size.width - 50, 35, 35, 35)
        settingsButton.setImage(UIImage(named: "settings-button"), forState: UIControlState.Normal)
        settingsButton.addTarget(self, action: Selector("settingsButtonPressed"), forControlEvents: UIControlEvents.TouchUpInside)

        self.view.addSubview(settingsButton)
}

func settingsButtonPressed(){
        println("Settings selected")
}

我没有收到任何错误，只是在我触摸按钮时没有注册。我也试过制作一个 UIButtonType.Custom 类型的按钮，我试过选择器作为

Selector("settingsButtonPressed")
Selector("settingsButtonPressed:") //I changed the function to settingsButtonPressed(sender: UIButton)
"settingsButtonPressed"
"settingsButtonPressed:" //I changed the function to settingsButtonPressed(sender: UIButton)