相关疑难解决方法(0)

给定一个包含噪声包围的已知模式的列表,是否有一种优雅的方式来获得与模式相同的所有项目.请参阅下面的原始代码.

list_with_noise = [7,2,1,2,3,4,2,1,2,3,4,9,9,1,2,3,4,7,4,3,1,2,3,5]
known_pattern = [1,2,3,4]
res = []


for i in list_with_noise:
    for j in known_pattern:
        if i == j:
            res.append(i)
            continue

print res

我们会得到的 2, 1, 2, 3, 4, 2, 1, 2, 3, 4, 1, 2, 3, 4, 4, 3

奖励:如果不存在完整模式,则避免附加i(即,允许1,2,3,4但不允许1,2,3)

例子:

find_sublists_in_list([7,2,1,2,3,4,2,1,2,3,4,9,9,1,2,3,4,7,4,3,1,2,3,5],[1,2,3,4])

[1,2,3,4],[1,2,3,4],[1,2,3,4]


find_sublists_in_list([7,2,1,2,3,2,1,2,3,6,9,9,1,2,3,4,7,4,3,1,2,6],[1,2,3,4])

[1,2,3],[1,2,3],[1,2,3]

列表包含命名元组.