如果输入是数组,则null表示没有节点。
输入:
[1, 2, 3, null, 5, null, 7]
请假设我已经检查了输入。
对于每个array[i],其父项array[i / 2]不会是null(递归地,所以 root 不能是null)。
如何构建具有这种逻辑关系的树:
1
/ \
2 3
\ \
5 7
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每个节点都应该由一个TreeNode对象表示:
class TreeNode {
public:
int val;
TreeNode *left;
TreeNode *right;
TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
};
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但是如果树如上所述不完整,如何整齐有效地完成它?
测试数据:
[输入数组]
[-64,12,18,-4,-53,null,76,null,-51,null,null,-93,3,null,-31,47,null,3,53,-81,33,4,null,-51,-44,-60,11,null,null,null,null,78,null,-35,-64,26,-81,-31,27,60,74,null,null,8,-38,47,12,-24,null,-59,-49,-11,-51,67,null,null,null,null,null,null,null,-67,null,-37,-19,10,-55,72,null,null,null,-70,17,-4,null,null,null,null,null,null,null,3,80,44,-88,-91,null,48,-90,-30,null,null,90,-34,37,null,null,73,-38,-31,-85,-31,-96,null,null,-18,67,34,72,null,-17,-77,null,56,-65,-88,-53,null,null,null,-33,86,null,81,-42,null,null,98,-40,70,-26,24,null,null,null,null,92,72,-27,null,null,null,null,null,null,-67,null,null,null,null,null,null,null,-54,-66,-36,null,-72,null,null,43,null,null,null,-92,-1,-98,null,null,null,null,null,null,null,39,-84,null,null,null,null,null,null,null,null,null,null,null,null,null,-93,null,null,null,98]