相关疑难解决方法(0)

我正在使用Scala Pickling,一个Scala的自动序列化框架.根据作者的幻灯片,T只要有隐含Pickler[T]的范围,任何类型都可以被腌制.在这里,我假设她的意思scala.tools.nsc.io.Pickler.但是,以下内容无法编译:

import scala.pickling._
import scala.pickling.binary._
import scala.tools.nsc.io.Pickler

object Foo {
  def bar[T: Pickler](t: T) = t.pickle
}

错误是:

[error] exception during macro expansion:
[error] scala.ScalaReflectionException: type T is not a class
[error]     at scala.reflect.api.Symbols$SymbolApi$class.asClass(Symbols.scala:323)
[error]     at scala.reflect.internal.Symbols$SymbolContextApiImpl.asClass(Symbols.scala:73)
[error]     at scala.pickling.PickleMacros$class.pickleInto(Macros.scala:381)
[error]     at scala.pickling.Compat$$anon$17.pickleInto(Compat.scala:33)
[error]     at scala.pickling.Compat$.PickleMacros_pickleInto(Compat.scala:34)

我正在使用Scala 2.10.2与scala-pickling 0.8-SNAPSHOT.

这是错误还是用户错误？

编辑1:同样的错误既出现scala.pickling.SPickler和scala.pickling.DPickler.

编辑2:看起来这是一个错误:https://github.com/scala/pickling/issues/31