相关疑难解决方法(0)

我要求Python打印一列CSV数据中的最小数字,但最上面一行是列号,我不希望Python考虑顶行.如何确保Python忽略第一行？

这是到目前为止的代码:

import csv

with open('all16.csv', 'rb') as inf:
    incsv = csv.reader(inf)
    column = 1                
    datatype = float          
    data = (datatype(column) for row in incsv)   
    least_value = min(data)

print least_value

你能解释一下你在做什么,而不只是给出代码吗？我对Python非常陌生,并希望确保我理解一切.

在这个问题中,我使用Python生成器进行了无休止的序列.但是相同的代码在Python 3中不起作用,因为它似乎没有next()功能.功能的等价物是什么next？

def updown(n):
    while True:
        for i in range(n):
            yield i
        for i in range(n - 2, 0, -1):
            yield i

uptofive = updown(6)
for i in range(20):
    print(uptofive.next())

我正在使用python 3.3.3.我正在从tutorialspoint.com上做教程.我无法理解这个错误是什么.

这是我的代码:

fo = open("foo.txt", "w")
print ("Name of the file: ", fo.name)

# Assuming file has following 5 lines
# This is 1st line
# This is 2nd line
# This is 3rd line
# This is 4th line
# This is 5th line

seq = ["This is 6th line\n", "This is 7th line"]
# Write sequence of lines at the end of the file.
fo.seek(0, 2)
line = fo.writelines( seq )

# Now read complete file from …