相关疑难解决方法(0)

我首先学习了C#,现在我开始使用C++.据我所知,newC++中的operator 与C#中的operator 不相似.

你能解释一下这个示例代码中内存泄漏的原因吗？

class A { ... };
struct B { ... };

A *object1 = new A();
B object2 = *(new B());

我的程序如下所示

#include <iostream>
#include <thread>

class A {
public:
    void foo(int n ) { std::cout << n << std::endl; }
};

int main()
{
    A a;

    std::thread t1(&A::foo, std::ref(a), 100);

    t1.join();
    return 0;
}

当我使用以下命令编译它时,我得到错误

g++ -o main main.cc -lpthread -std=c++11

错误:

In file included from /usr/local/include/c++/4.8.2/thread:39:0,
                  from check.cc:2:
/usr/local/include/c++/4.8.2/functional: In instantiation of ‘struct std::_Bind_simple<std::_Mem_fn<void (A::*)(int)>(std::reference_wrapper<A>, int)>’:
/usr/local/include/c++/4.8.2/thread:137:47:   required from ‘std::thread::thread(_Callable&&, _Args&& ...) [with _Callable = void (A::*)(int); _Args = {std::reference_wrapper<A>, int}]’
check.cc:13:42:   required from here
/usr/local/include/c++/4.8.2/functional:1697:61: error?no type named …