相关疑难解决方法(0)

我试图从照片库中选择一个图像文件并写入SD卡.以下是导致异常的代码.在尝试创建FileOutputStream时,它似乎抛出此异常.我将以下行添加到嵌套在application元素中的清单文件中.我找不到问题的解决方案:

<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" />

public boolean saveSelectedImage( Uri selectedImage, int imageGroup,
        int imageNumber )
{
    boolean exception = false;
    InputStream input = null;
    OutputStream output = null;
    if( externalStorageIsWritable() )
    {
        try
        {
            ContentResolver content = ctx.getContentResolver();
            input = content.openInputStream( selectedImage );
            if(input != null) Log.v( CLASS_NAME, "Input Stream Opened successfully");
            File outFile = null;

            File root = Environment.getExternalStorageDirectory(  );
            if(root == null) Log.v(CLASS_NAME, "FAILED TO RETRIEVE DIRECTORY");
            else Log.v(CLASS_NAME, "ROOT DIRECTORY is:"+root.toString());

            output = new FileOutputStream( root+"/Image"+ imageGroup + …

正如你可以从标题中注意到的那样,我在Android中将文件写入sdcard时遇到了问题.我已经检查了这个问题,但它没有帮助我.我想写一个将在sdcard上的公共空间中的文件,以便任何其他应用程序都可以读取它.

首先,我检查是否安装了SD卡:

Environment.getExternalStorageState();

然后,我运行此代码:

File baseDir = Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_DOWNLOADS);
    baseDir.mkdirs();
    File file = new File(baseDir, "file.txt");
    try {
        FileOutputStream out = new FileOutputStream(file);
        out.flush();
        out.close();
        Log.d("NEWFILE", file.getAbsolutePath());
    } catch (IOException e) {
        e.printStackTrace();
    }

我有:

<manifest>
    <uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" />

<application>
...
</application>
</manifest>

在我的AndroidManifest.xml中.

确切的错误是这样的:

java.io.FileNotFoundException: /storage/1510-2908/Download/secondFile.txt: open failed: EACCES (Permission denied)

我正在模拟器上测试我的代码(模拟Nexus5 API 23).我所需的最低SDK版本是19(4.4 Kitkat).

此外,一切正常,使用相同的代码将文件写入SD卡上的私人文件夹,所以我说前代码也应该工作:

File newFile = new File(getExternalFilesDir(Environment.DIRECTORY_DOWNLOADS), "esrxdtcfvzguhbjnk.txt");
    newFile.getParentFile().mkdirs();
    try {
        FileOutputStream out = new FileOutputStream(newFile);
        out.flush();
        out.close();
        Log.d("NEWFILE", newFile.getAbsolutePath());
    } catch (IOException e) …

我需要将一些数据保存到SD卡,我已经将权限添加到AndroidManifest.xml文件中,当我在Android 4.12 mobile中测试它时,我可以得到正确的结果.

但是当我在Android 5.1移动设备中测试它时,我打开失败:EACCES(Permission denied)错误,为什么？

顺便说一句,我已经阅读了Android 6.0开放失败:EACCES(Permission denied)和Exception'开放失败:EACCES(Permission denied)'在Android上,但现在我的手机是SamSung Android 5.1

码

 private void ActionUploadFiles(Map<String, String> files,IHTTPSession session,String uploadFolder){

        try{
            Set<String> keys = files.keySet();

            for (String key:keys) {
                String location = files.get(key);
                File source = new File(location);

                String filename= session.getParms().get(key);
                filename=FilenameUtils.getName(filename);

                File target = new File(uploadFolder,filename);

                FileUtils.copyFile(source,target);
            }
        }
        catch (Exception e) {
            Utility.LogError("Upload Error: "+ e.getMessage());
        }
    }

AndroidManifest.xml中

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
    package="info.dodata.wifi">

    <uses-permission android:name="android.permission.INTERNET"/>
    <uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
    <uses-permission android:name="android.permission.ACCESS_WIFI_STATE"></uses-permission>

    <uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE" …

当我尝试将位图存储到存储中时出现此错误 #

    File path = new File(Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_PICTURES), "picture");
    if (! path.exists()) {
        path.mkdirs();
        if (!path.exists()) {
            return null;
        }
    }
    String timeStamp = new SimpleDateFormat("yyyyMMdd_HH_mm_ss", Locale.CHINA).format(new Date());
    File imagePath = new File(path.getPath() + "_" + "IMG_" + timeStamp + ".jpg");
    BufferedOutputStream fos;
    try {
        fos =new BufferedOutputStream(new FileOutputStream(imagePath));
        bitmap.compress(Bitmap.CompressFormat.PNG, 100, fos);
        fos.flush();
        fos.close();
        return imagePath;
    } catch (FileNotFoundException e) {
        Log.e("GREC", e.getMessage(), e);
        return null;
    } catch (IOException e) {
        Log.e("GREC", e.getMessage(), e);
        return null;
    }

fos = new BufferedOutputStream(new …