相关疑难解决方法(0)

有没有办法通过引用SASS中的另一个函数或mixin来传递函数或mixin，然后调用引用的函数或mixin？

例如：

@function foo($value) {
    @return $value;
}

@mixin bob($fn: null) {
    a {
        b: $fn(c); // is there a way to call a referenced function here?
    }
}

@include bob(foo); // is there any way I can pass the function "foo" here?