相关疑难解决方法(0)

我想迭代一个文件列表.这个列表是find命令的结果,所以我想出了:

getlist() {
  for f in $(find . -iname "foo*")
  do
    echo "File found: $f"
    # do something useful
  done
}

没关系,除非文件名中有空格:

$ ls
foo_bar_baz.txt
foo bar baz.txt

$ getlist
File found: foo_bar_baz.txt
File found: foo
File found: bar
File found: baz.txt

我该怎么做才能避免空格分裂？

我有以下shell脚本.目的是循环到目标文件的每一行(其路径是脚本的输入参数)并对每一行进行操作.现在,它似乎只适用于目标文件中的第一行,并在该行被处理后停止.我的剧本有什么问题吗？

#!/bin/bash
# SCRIPT: do.sh
# PURPOSE: loop thru the targets 

FILENAME=$1
count=0

echo "proceed with $FILENAME"

while read LINE; do
   let count++
   echo "$count $LINE"
   sh ./do_work.sh $LINE
done < $FILENAME

echo "\ntotal $count targets"

在do_work.sh,我运行了几个ssh命令.

我无法运行它，因为Java仅等待ffmpeg。但是ffmpeg不提供输入-也不提供错误流。它只是运行，但是什么也没做。

插入bash的“ System.out.println（” command：..“）的输出按预期运行正常。因此ffm​​peg语法没有问题。

这是代码。

package mypackage;

import java.awt.image.BufferedImage;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import javax.imageio.ImageIO;

/**
 *
 * @author test
 */
public class ffmpeg_hang {

        /**
     * @param args the command line arguments
     */
    public static void main(String[] args) throws IOException, InterruptedException {
        String INPUT_FILE="/path/to/media";
        String FFMPEG_PATH="/path/to/ffmpegFolder/";

            for(int i=0;(i+4)<40;i+=4){                
            String[] ffmpeg_pipe = new String[]{
                FFMPEG_PATH + "ffmpeg_4.1.1",
                "-ss",(i+""),"-t", "4",             
                "-i", INPUT_FILE,                                        
                "-ac", "1", "-acodec", "pcm_s16le", "-ar", "16000", 
                "-f","nut","-","|",
                FFMPEG_PATH + "ffmpeg_4.1.1",
                "-i","-",
                "-lavfi", "showspectrumpic=s=128x75:legend=disabled:saturation=0:stop=8000",
                "-f","image2pipe","pipe:1"};

            System.out.println("command: "+String.join(" ", …

我有一个bash脚本,我需要遍历find命令的输出的每一行,但看起来我正在从find命令迭代每个Word(空格分隔).到目前为止我的脚本看起来像这样:

folders=`find -maxdepth 1 -type d`

for $i in $folders
do
    echo $i
done

我希望这会给出如下输出:

./dir1 and foo
./dir2 and bar
./dir3 and baz

但我得到这样的输出:

./dir1
and
foo
./dir2
and
bar
./dir3
and
baz

我在这做错了什么？

几年前，当我还年轻、无忧无虑、呃、不太了解编写 shell 脚本的良好实践时；我编写了一个快速而肮脏的脚本来协助完成我面临的任务：

#!/bin/bash                                                                                                         

# autohighlighter which generates highlights from a video clip and file                                             

process_highlight_file() {                                                                                          
        n=0                                                                                                         
        while read -r line; do                                                                                      
                begin=$(echo "$line" | awk '{ print $1 }' )                                                         
                end=$(echo "$line" | awk '{ print $2 }')                                                            
                hilightname=$(echo "$line" | awk '{ print $3 }')                                                    
                printf "Begin highlight called %s at %s, to %s\n" "$hilightname" "$begin" "$end"                   
                echo "$begin $end"                                                                                 
                sleep 2                                                                                             
                echo "ffmpeg -y -ss $begin -i $videofile -to $end -c copy -avoid_negative_ts 1 …