相关疑难解决方法(0)

这个问题是关于如何读/写,分配和管理位图的像素数据.

下面是一个如何为像素数据分配字节数组(托管内存)并使用它创建位图的示例:

Size size = new Size(800, 600);
PixelFormat pxFormat = PixelFormat.Format8bppIndexed;
//Get the stride, in this case it will have the same length of the width.
//Because the image Pixel format is 1 Byte/pixel.
//Usually stride = "ByterPerPixel"*Width

//但并非总是如此.更多信息在bobpowell.

int stride = GetStride(size.Width, pxFormat);
byte[] data = new byte[stride * size.Height];
GCHandle handle = GCHandle.Alloc(data, GCHandleType.Pinned);
Bitmap bmp = new Bitmap(size.Width, size.Height, stride,
             pxFormat, handle.AddrOfPinnedObject());

//After doing your stuff, free the Bitmap and unpin the array.
bmp.Dispose(); …

我制作此代码以接收图像并将其转换为位图图像,但它不起作用.

这是代码:

public void ReceiveImage()
{
    NetworkStream stream = new NetworkStream(socket);
    byte[] data = new byte[4];
    stream.read(data,0,data.length,0)
    int size = BitConverter.ToInt32(data,0);
    data = new byte[size];
    stream.read(data,0,data.length)
    MemoryStream imagestream = new MemoryStream(data);
    Bitmap bmp = new Bitmap(imagestream);
    picturebox1.Image = bmp;
}

它得到:

Bitmap bmp = new Bitmap(imagestream);

并给我这个错误:

参数无效