相关疑难解决方法(0)

我正在使用以下代码进行httpPost调用,但是当我尝试在chrome扩展中的"简单休息客户端"中提供以下参数时,它返回了400个错误的请求它可以正常工作任何人指导我在这里做了什么错误？

简单休息客户端我输入以下内容:

URL:http://jon2012.com/api/register 方法:POST标题:没有标题,因为它们不是必需的数据:{"email":"test@example.com","first_name":"名称"}

Android代码:

HttpClient client = new DefaultHttpClient();
        HttpConnectionParams.setConnectionTimeout(client.getParams(), 10000); //Timeout Limit
        HttpResponse response;
        JSONObject json = new JSONObject();
        try{
            HttpPost post = new HttpPost(url);
            json.put("email", email);
            json.put("first_name", name);
            StringEntity se = new StringEntity( "JSON: " + json.toString());  
            se.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
            post.setEntity(se);
            response = client.execute(post);
            /*Checking response */
            /*if(response!=null){
                InputStream in = response.getEntity().getContent(); //Get the data in the entity
*/
            int statusCode = response.getStatusLine().getStatusCode();

        }
        catch(Exception e){
            e.printStackTrace();
           // createDialog("Error", "Cannot Estabilish Connection");
        }

任何帮助都会得到满足

我必须向Web服务发送请求,以使用用户名和密码对用户进行身份验证.

我对以下帖子请求有疑问:

public String postTest(String action, ConnectionParametrData [] parameters) {
        Uri.Builder builder = new Uri.Builder().scheme(scheme).authority(authority).path(action);
        uri = builder.build();
        BufferedReader in = null;
        String ans = null;
        HttpPost request = new HttpPost(uri.toString());
        HttpClient defaultClient = new DefaultHttpClient();
        try {
            request.setHeader("Content-Type", "application/x-www-form-urlencoded");
            request.setEntity(new UrlEncodedFormEntity(getValuePairs(parameters)));
            HttpResponse response = defaultClient.execute(request);
            in = new BufferedReader(new InputStreamReader(response.getEntity().getContent(), "UTF-8"), 8192);
            StringBuffer sb = new StringBuffer("");
            String line = "";
            String newLine = System.getProperty("line.separator");
            while((line = in.readLine()) != null) {
                sb.append(line + newLine);
            }
            ans = sb.toString();
        } …

我正在尝试连接到groovehark API,这是http请求

POST URL
http://api.grooveshark.com/ws3.php?sig=f699614eba23b4b528cb830305a9fc77
POST payload
{"method":'addUserFavoriteSong",'parameters":{"songID":30547543},"header": 
{"wsKey":'key","sessionID":'df8fec35811a6b240808563d9f72fa2'}}

我的问题是如何通过Java发送此请求？