相关疑难解决方法(0)

我想编写一个将CamelCase转换为人类可读名称的方法.

这是测试用例:

public void testSplitCamelCase() {
    assertEquals("lowercase", splitCamelCase("lowercase"));
    assertEquals("Class", splitCamelCase("Class"));
    assertEquals("My Class", splitCamelCase("MyClass"));
    assertEquals("HTML", splitCamelCase("HTML"));
    assertEquals("PDF Loader", splitCamelCase("PDFLoader"));
    assertEquals("A String", splitCamelCase("AString"));
    assertEquals("Simple XML Parser", splitCamelCase("SimpleXMLParser"));
    assertEquals("GL 11 Version", splitCamelCase("GL11Version"));
}

我正在使用此函数将CamelCase转换为虚线字符串:

function camel2dashed($className) {
    return strtolower(preg_replace('/([^A-Z-])([A-Z])/', '$1-$2', $className));
}

它有点工作但是当我有前任时有问题.这个字符串:getADog.它返回get-adog但我想要get-a-dog

我该如何更改我的代码？谢谢

我现在有一个方法将我的驼峰案例字符串转换为蛇案例,但它分为三个调用preg_replace():

public function camelToUnderscore($string, $us = "-")
{
    // insert hyphen between any letter and the beginning of a numeric chain
    $string = preg_replace('/([a-z]+)([0-9]+)/i', '$1'.$us.'$2', $string);
    // insert hyphen between any lower-to-upper-case letter chain
    $string = preg_replace('/([a-z]+)([A-Z]+)/', '$1'.$us.'$2', $string);
    // insert hyphen between the end of a numeric chain and the beginning of an alpha chain
    $string = preg_replace('/([0-9]+)([a-z]+)/i', '$1'.$us.'$2', $string);

    // Lowercase
    $string = strtolower($string);

    return $string;
}

我编写了测试来验证其准确性,并且它可以正常使用以下输入数组(array('input' => 'output')):

$test_values = [
    'foo' …

在R中,我想转换

c("ThisText", "NextText")

至

c("this.text", "next.text")

这是反向这个SO问题,和同为这一个,但与R中的点,而不是在下划线PHP.