相关疑难解决方法(0)

我知道曾经有一种方法可以通过apache commons来获取它,如下所示:http: //hc.apache.org/httpclient-legacy/apidocs/org/apache/commons/httpclient/HttpMethod.html 以及此处的示例:

http://www.kodejava.org/examples/416.html

但我相信这已被弃用了.是否还有其他方法可以在java中生成http get请求并将响应主体作为字符串而不是流来获取？

我有一个Android客户端,通过REST-ful端点和JSON与服务器通信.因此,我需要在将其转换为Hash之前检索完整的服务器响应.我有这个代码(在互联网上找到的地方):

private static String convertStreamToString(InputStream is) {

    BufferedReader reader = new BufferedReader(new InputStreamReader(is));
    StringBuilder sb = new StringBuilder();

    String line = null;
    try {
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
    } catch (IOException e) {
        e.printStackTrace();
    } finally {
        try {
            is.close();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
    return sb.toString();
}

代码在大多数情况下都有效,但是我看到来自具有OutOfMemory异常的客户端在该字段中崩溃的报告:

    while ((line = reader.readLine()) != null) {

完整的堆栈跟踪是:

java.lang.RuntimeException: An error occured while executing doInBackground()
    at android.os.AsyncTask$3.done(AsyncTask.java:200)
    at java.util.concurrent.FutureTask$Sync.innerSetException(FutureTask.java:273)
    at java.util.concurrent.FutureTask.setException(FutureTask.java:124) …

我从成千上万的角色成长为指数大的String test += str;地方test.运行需要45分钟,可能是因为创建了大字符串并删除了垃圾.然后,我将这样的输入交错,使其达到30秒.

这似乎是一种廉价的方式,但效果很好:

  if (secondDump.length() > 50)
  {
     intermedDump = intermedDump + secondDump;
     secondDump = "";
  }      

  if (intermedDump.length() > 100)
  {
     thirdDump = thirdDump + intermedDump;
     intermedDump = "";
  }
  if (thirdDump.length() > 500)
  {
     fourthDump = fourthDump + thirdDump;
     thirdDump = "";
  }
  if (fourthDump.length() > 1000)
  {
     fifthDump = fifthDump + fourthDump;
     fourthDump = "";
  }
  //with just this and not sixth.  Runtime>>>> : 77343
  if (fifthDump.length() > 5000)
  {
     sixthDump …