我不确定这是否更像是一个操作系统问题,但我想我会问这里,以防任何人从Python的结尾有一些见解.
我一直在尝试使用一个CPU密集型for循环joblib,但是我发现不是将每个工作进程分配给不同的核心,我最终将它们全部分配到同一个核心而没有性能提升.
这是一个非常简单的例子......
from joblib import Parallel,delayed
import numpy as np
def testfunc(data):
# some very boneheaded CPU work
for nn in xrange(1000):
for ii in data[0,:]:
for jj in data[1,:]:
ii*jj
def run(niter=10):
data = (np.random.randn(2,100) for ii in xrange(niter))
pool = Parallel(n_jobs=-1,verbose=1,pre_dispatch='all')
results = pool(delayed(testfunc)(dd) for dd in data)
if __name__ == '__main__':
run()
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...这是我在htop脚本运行时看到的内容:

我在一台4核的笔记本电脑上运行Ubuntu 12.10(3.5.0-26).显然joblib.Parallel是为不同的工作者生成单独的进程,但有没有办法让这些进程在不同的内核上执行?
我试图在Python中实现大量的矩阵 - 矩阵乘法.最初,我假设NumPy将自动使用我的线程BLAS库,因为我是针对这些库构建的.但是,当我查看顶部或其他内容时,似乎代码根本不使用线程.
任何想法是什么错误或我可以做些什么来轻松使用BLAS性能?
我正在运行Mac OS X 10.6.8并使用Enthought Python Distribution.我想要numpy函数来利用我的核心.我遇到了类似于这篇文章的问题:python/numpy中的多线程blas但是在完成该海报的步骤之后,我仍然遇到同样的问题.这是我的numpy.show_config():
lapack_opt_info:
libraries = ['mkl_lapack95_lp64', 'mkl_intel_lp64', 'mkl_intel_thread', 'mkl_core', 'mkl_mc', 'mkl_mc3', 'pthread']
library_dirs = ['/Library/Frameworks/EPD64.framework/Versions/1.4.2/lib']
define_macros = [('SCIPY_MKL_H', None)]
include_dirs = ['/Library/Frameworks/EPD64.framework/Versions/1.4.2/include']
blas_opt_info:
libraries = ['mkl_intel_lp64', 'mkl_intel_thread', 'mkl_core', 'mkl_mc', 'mkl_mc3', 'pthread']
library_dirs = ['/Library/Frameworks/EPD64.framework/Versions/1.4.2/lib']
define_macros = [('SCIPY_MKL_H', None)]
include_dirs = ['/Library/Frameworks/EPD64.framework/Versions/1.4.2/include']
lapack_mkl_info:
libraries = ['mkl_lapack95_lp64', 'mkl_intel_lp64', 'mkl_intel_thread', 'mkl_core', 'mkl_mc', 'mkl_mc3', 'pthread']
library_dirs = ['/Library/Frameworks/EPD64.framework/Versions/1.4.2/lib']
define_macros = [('SCIPY_MKL_H', None)]
include_dirs = ['/Library/Frameworks/EPD64.framework/Versions/1.4.2/include']
blas_mkl_info:
libraries = ['mkl_intel_lp64', 'mkl_intel_thread', 'mkl_core', 'mkl_mc', 'mkl_mc3', 'pthread']
library_dirs = …Run Code Online (Sandbox Code Playgroud)