相关疑难解决方法(0)

我正在使用这些Scanner方法nextInt()并nextLine()阅读输入.

它看起来像这样:

System.out.println("Enter numerical value");    
int option;
option = input.nextInt(); // Read numerical value from input
System.out.println("Enter 1st string"); 
String string1 = input.nextLine(); // Read 1st string (this is skipped)
System.out.println("Enter 2nd string");
String string2 = input.nextLine(); // Read 2nd string (this appears right after reading numerical value)

问题是输入数值后,第一个input.nextLine()被跳过而第二个input.nextLine()被执行,所以我的输出如下所示:

Enter numerical value
3   // This is my input
Enter 1st string    // The program is supposed to stop here and …

这个程序实际上如何工作......？

import java.util.Scanner;

class string
{
    public static void main(String a[]){
        int a;
        String s;
        Scanner scan = new Scanner(System.in);

        System.out.println("enter a no");
        a = scan.nextInt();
        System.out.println("no is ="+a);

        System.out.println("enter a string");
        s = scan.nextLine();
        System.out.println("string is="+s);
    }
}

输出是:

enter the no
1234
no is 1234
enter a string
string is=         //why is it not allowing me to enter a string here?