相关疑难解决方法(0)

编译一些简单的c ++代码时出错

我尝试在osx lion上编译这个cpp代码,但是我收到了一个错误.

#include <iostream> 

using namespace std; 

int main (int argc, char *argv[]) 
{ 
    for(int i = 0; i < 10; i++) 
    { 
        cout << "hi"; 
        cout << endl; 
    } 

    return 0; 
}
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编译:

cc main.cpp
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错误:

Undefined symbols for architecture x86_64:
  "std::cout", referenced from:
      _main in ccBdbc76.o
  "std::basic_ostream<char, std::char_traits<char> >& std::operator<< <std::char_traits<char> >(std::basic_ostream<char, std::char_traits<char> >&, char const*)", referenced from:
      _main in ccBdbc76.o
  "std::basic_ostream<char, std::char_traits<char> >& std::endl<char, std::char_traits<char> >(std::basic_ostream<char, std::char_traits<char> >&)", referenced from:
      _main in ccBdbc76.o
  "std::basic_ostream<char, std::char_traits<char> >::operator<<(std::basic_ostream<char, std::char_traits<char> …
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c++ macos linker-errors

42
推荐指数
2
解决办法
5万
查看次数

在 iOS 应用程序中链接静态库后架构 arm64 的未定义符号

我正在创建一个示例静态库以在我的 iOS 应用程序中使用,但是,在调用静态库的方法时,我遇到了链接器错误:

Undefined symbols for architecture arm64:
"_doMath", referenced from:
  _doMathInterface in libTestMain.a(Test.o)
 (maybe you meant: _doMathInterface)
ld: symbol(s) not found for architecture arm64
clang: error: linker command failed with exit code 1 (use -v to see invocation)
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这是静态库的结构:

我有一个头文件 Test.h:

#import <Foundation/Foundation.h>

@interface Test : NSObject

int doMathInterface(int a, int b);

@end
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及其实现 Test.m :

#import "Test.h"
#include "PaymentAPI.h"

@implementation Test

int doMathInterface(int a, int b){
    return doMath(a, b);
}

@end
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在 PaymentAPI.h 中:

#ifndef PaymentAPI_h
#define PaymentAPI_h …
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c++ xcode static-libraries ios

6
推荐指数
1
解决办法
597
查看次数

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