相关疑难解决方法(0)

我有一个关于处理m2m /通过模型及其在django rest框架中的表示的问题.我们来看一个经典的例子:

models.py:

from django.db import models

class Member(models.Model):
    name = models.CharField(max_length = 20)
    groups = models.ManyToManyField('Group', through = 'Membership')

class Group(models.Model):
    name = models.CharField(max_length = 20)

class Membership(models.Model):
    member = models.ForeignKey('Member')
    group = models.ForeignKey('Group')
    join_date = models.DateTimeField()

serializers.py:

imports...

class MemberSerializer(ModelSerializer):
    class Meta:
        model = Member

class GroupSerializer(ModelSerializer):
    class Meta:
        model = Group

views.py:

imports...

class MemberViewSet(ModelViewSet):
    queryset = Member.objects.all()
    serializer_class = MemberSerializer

class GroupViewSet(ModelViewSet):
    queryset = Group.objects.all()
    serializer_class = GroupSerializer

在获取成员实例时,我成功接收了所有成员的字段及其组 - 但是我只获得了组的详细信息,而没有来自成员模型的额外详细信息.

换句话说,我希望收到:

{ …

该模型定义了Article和Author类。它们以多对多的关系链接在一起。此关系是通过自定义中介表定义的：

# models.py
class Article(models.Model):
    title = models.CharField(max_length=500)
    authors = models.ManyToManyField(Author, through='AuthorOrder')

class Author(models.Model):
    name = models.CharField(max_length=255)

class AuthorOrder(models.Model):
    author = models.ForeignKey(Author)
    article = models.ForeignKey(Article)
    writing_order = models.IntegerField()

序列化应返回如下JSON：

#articles_json
{"fields":
     {
         "title": "A title",
         "authors": [
             {
                 "name":"Author 1",
                 "writing_order": 1
             },
             {
                 "name":"Author 2",
                 "writing_order": 2
             }
         }
     }
}

我确定了两种解决方案。

• 此建议建议单独序列化AuthorOrder字段。
• 第二个是使用Django Rest Framework。

我尝试了两者，但没有成功。您知道另一种方法吗？