相关疑难解决方法(0)

根据哪些逻辑super.onDestroy();在析构函数中排在最前面？例如:

protected void onDestroy() {        
    super.onDestroy();
    releaseMediaPlayer();
}

并不是:

protected void onDestroy() {        
    releaseMediaPlayer();
    super.onDestroy();
}

就像在c ++,obj-c,pascal等？

凡在onStart(),onStop(),onDestroy()的活动我打电话super.onStart(),super.onStop(),super.onDestroy()？

可以在该onActivityResult(int requestCode, int resultCode, Intent data)方法中读取语音识别的结果,如该示例中所示.这个方法在类中重写了相同的方法Activity:为什么对超类方法的调用不是第一个语句？

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    if (requestCode == VOICE_RECOGNITION_REQUEST_CODE && resultCode == RESULT_OK) {
        // Fill the list view with the strings the recognizer thought it could have heard
        // ...
    }

    super.onActivityResult(requestCode, resultCode, data);
}

我有android viewpager幻灯片的问题.我希望在最短时间后显示viewpager布局.这是我的代码示例. 我的主要课程:

public class MainActivity extends Activity {
    private ViewPager mViewPager;
    private SwipeAdapter adapter;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        mViewPager = (ViewPager) findViewById(R.id.pager);
        // set the adapter
        adapter = new SwipeAdapter(MainActivity.this);
        mViewPager.setAdapter(adapter);

        mViewPager.setOnPageChangeListener(new OnPageChangeListener() {

            @Override
            public void onPageSelected(int position) {
            }

            @Override
            public void onPageScrolled(int arg0, float arg1, int arg2) {
            }
            @Override
            public void onPageScrollStateChanged(int arg0) {
            }
        });
    }

}

我的适配器类:

public class SwipeAdapter extends PagerAdapter {

    private LayoutInflater mInflater;
    private static int[] …

WAY1:

@Override
protected void onPause() {
    super.onPause();
    // do something urgent
    doSomething();
}

WAY2:

@Override
protected void onPause() {
    // do something urgent
    doSomething();
    super.onPause();
}

所不同的是调用顺序doSomething()和super.onPause().当我使用WAY1时,如果doSomething()成本太高,我会得到错误:W/ActivityManager( 4347): Activity pause timeout for ActivityRecord.

pause timeout如果我使用WAY2,我会避免错误吗？

我检查了AOSP,但是我很难理解Activity的调用过程.

在覆盖活动的ondestroy时,我应该在super.onDestroy()之前或之后放置命令吗？

protected void onDestroy() {

    //option 1: callback before or ...

    super.onDestroy();

    //option 2: callback after super.onDestroy();
}

(现在我担心:如果super.onDestroy太快,它将永远不会到达选项2.)