相关疑难解决方法(0)

我想从我的联系人列表中选择一个联系人.我读了很多解决方案和研究几周,但所有文章都没有正常工作.一些代码如下:

Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);
startActivityForResult(intent, PICK_CONTACT);

//并且在activityresult中:

if (resultCode == Activity.RESULT_OK) {
            Uri contactData = data.getData();
            Cursor c =  managedQuery(contactData, null, null, null, null);
            if (c.moveToFirst()) {
              String name = c.getString(c.getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME));
              tv1.setText(name);
            }
          }

或者此代码用于获取所有联系人但我不能拥有联系人数量:

String[] contacts = new String[] {People.NAME, People.NUMBER};       
Uri contentUri = People.CONTENT_URI;        
Cursor cursor = managedQuery(contentUri, contacts, null, null, null);                 
String textContacts = "";                 
if (cursor.moveToFirst()) {         
    String myname = null;         
    String mynumber = null;         
    do {          
        textContacts = textContacts + cursor.getString(cursor.getColumnIndex(People.NAME)) + …

您好我想从我们的默认联系簿意图中选择一个联系人.我尝试了几种方法来做到这一点.请在下面找到代码.所有这些代码的问题在于,他们打开一个中间文档屏幕,用户必须选择联系人,而不是打开联系簿.

private void openContactIntent() {
     Intent intent = new Intent(Intent.ACTION_GET_CONTENT, ContactsContract.Contacts.CONTENT_URI);
     intent.setType(ContactsContract.CommonDataKinds.Phone.CONTENT_ITEM_TYPE);
     startActivityForResult(intent, REQ_CONTACT_DIRECTORY);
}

我也试过了

Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);
startActivityForResult(intent, PICK_CONTACT);

和

Intent intent = new Intent(Intent.ACTION_PICK);
intent.setType(ContactsContract.Contacts.CONTENT_TYPE);
startActivityForResult(intent, PICK_CONTACT); 

我所看到的中间屏幕是