相关疑难解决方法(0)

将结果转换为Throwable.getStackTrace()描述堆栈跟踪的字符串的最简单方法是什么？

在Android(Java)中,如何打印出完整的堆栈跟踪？如果我的应用程序从nullPointerException或其他东西崩溃,它会打印出一个(几乎)完整的堆栈跟踪,如下所示:

java.io.IOException: Attempted read from closed stream.
com.android.music.sync.common.SoftSyncException: java.io.IOException: Attempted read from closed stream.
    at com.android.music.sync.google.MusicSyncAdapter.getChangesFromServerAsDom(MusicSyncAdapter.java:545)
    at com.android.music.sync.google.MusicSyncAdapter.fetchDataFromServer(MusicSyncAdapter.java:488)
    at com.android.music.sync.common.AbstractSyncAdapter.download(AbstractSyncAdapter.java:417)
    at com.android.music.sync.common.AbstractSyncAdapter.innerPerformSync(AbstractSyncAdapter.java:313)
    at com.android.music.sync.common.AbstractSyncAdapter.onPerformLoggedSync(AbstractSyncAdapter.java:243)
    at com.google.android.common.LoggingThreadedSyncAdapter.onPerformSync(LoggingThreadedSyncAdapter.java:33)
    at android.content.AbstractThreadedSyncAdapter$SyncThread.run(AbstractThreadedSyncAdapter.java:164)
Caused by: java.io.IOException: Attempted read from closed stream.
    at org.apache.http.impl.io.ChunkedInputStream.read(ChunkedInputStream.java:148)
    at org.apache.http.conn.EofSensorInputStream.read(EofSensorInputStream.java:159)
    at java.util.zip.GZIPInputStream.readFully(GZIPInputStream.java:212)
    at java.util.zip.GZIPInputStream.<init>(GZIPInputStream.java:81)
    at java.util.zip.GZIPInputStream.<init>(GZIPInputStream.java:64)
    at android.net.http.AndroidHttpClient.getUngzippedContent(AndroidHttpClient.java:218)
    at com.android.music.sync.api.MusicApiClientImpl.createAndExecuteMethod(MusicApiClientImpl.java:312)
    at com.android.music.sync.api.MusicApiClientImpl.getItems(MusicApiClientImpl.java:588)
    at com.android.music.sync.api.MusicApiClientImpl.getTracks(MusicApiClientImpl.java:638)
    at com.android.music.sync.google.MusicSyncAdapter.getChangesFromServerAsDom(MusicSyncAdapter.java:512)
    ... 6 more

但有时,出于调试目的,我想从代码中的位置记录完整的堆栈跟踪.我想我可以这样做:

StackTraceElement trace = new Exception().getStackTrace();
Log.d("myapp", trace.toString());

但是这只是打印出指向对象的指针......我是否必须遍历所有堆栈跟踪元素才能将它们打印出来？或者有一种简单的方法可以将它全部打印出来吗？

在Java 7中,是否有可能将Exception对象转换为Json？

例:

try {      
    //something
} catch(Exception ex) {     
    Gson gson = new Gson();
    System.out.println(gson.toJson(ex));
}