相关疑难解决方法(0)

我上课了 PersonList

[XmlRoot("Persons")]
PersonList : List<Human>

当我将其序列化为XML时,默认情况下会生成如下内容:

<Persons>
  <Human>...</Human>
  <Human>...</Human>
</Persons>

我的问题是需要以改变元素做什么Human,以Person输出？所以输出将是:

<Persons>
  <Person>...</Person>
  <Person>...</Person>
</Persons>

并且,如何将上述XML反序列化为PersonList类对象？

Per Nick的建议,这是我的测试代码:

[XmlRoot("Persons")]
public class Persons : List<Human>
{

}

[XmlRoot("Person")]
public class Human
{
    public Human()
    {
    }

    public Human(string name)
    {
        Name = name;
    }

    [XmlElement("Name")]
    public string Name { get; set; }

}

void TestXmlSerialize()
{
    Persons personList = new Persons();
    personList.Add(new Human("John"));
    personList.Add(new Human("Peter"));

    try
    {
        using (StringWriter writer = new StringWriter())
        { …