相关疑难解决方法(0)

我正在尝试使用LinqToXSD创建XML数据绑定类和包含许多导入模式的XML模式.所有模式都位于此处.

为此,我使用了以下根模式文档:

<?xml version="1.0" encoding="utf-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:TmatsG="http://www.spiraltechinc.com/tmats/106-13/TmatsG" elementFormDefault="unqualified">
    <xs:import namespace="http://www.spiraltechinc.com/tmats/106-13/TmatsCommon" schemaLocation="TmatsCommonTypes.xsd"/>
    <xs:import namespace="http://www.spiraltechinc.com/tmats/106-13/TmatsC" schemaLocation="TmatsCGroup.xsd"/>
    <xs:import namespace="http://www.spiraltechinc.com/tmats/106-13/TmatsD" schemaLocation="TmatsDGroup.xsd"/>
    <xs:import namespace="http://www.spiraltechinc.com/tmats/106-13/TmatsG" schemaLocation="TmatsGGroup.xsd"/>
    <xs:import namespace="http://www.spiraltechinc.com/tmats/106-13/TmatsH" schemaLocation="TmatsHGroup.xsd"/>
    <xs:import namespace="http://www.spiraltechinc.com/tmats/106-13/TmatsM" schemaLocation="TmatsMGroup.xsd"/>
    <xs:import namespace="http://www.spiraltechinc.com/tmats/106-13/TmatsP" schemaLocation="TmatsPGroup.xsd"/>
    <xs:import namespace="http://www.spiraltechinc.com/tmats/106-13/TmatsR" schemaLocation="TmatsRGroup.xsd"/>
    <xs:import namespace="http://www.spiraltechinc.com/tmats/106-13/TmatsS" schemaLocation="TmatsSGroup.xsd"/>
    <xs:import namespace="http://www.spiraltechinc.com/tmats/106-13/TmatsT" schemaLocation="TmatsTGroup.xsd"/>
    <xs:import namespace="http://www.spiraltechinc.com/tmats/106-13/TmatsV" schemaLocation="TmatsVGroup.xsd"/>
    <xs:element name="Tmats" type="TmatsG:Tmats">
        <xs:annotation>
            <xs:documentation>Tmats Root</xs:documentation>
        </xs:annotation>
    </xs:element>
</xs:schema>

我使用Linq到XSD创建了类.然后我写了以下测试:

[TestMethod()]
public void TmatsXmlExample4()
{
    Tmats tmats = new Tmats
    {
        ProgramName = "My Program",
        OriginationDate = DateTime.Now,
    };
    tmats.PointOfContact.Add(new PointOfContactType
    {
         Address = "12345 …