相关疑难解决方法(0)

MyCustomObject * object=new MyCustomObject();

假设我的许多类都使用了对象指针,但突然间我想改变指针的内容而不改变地址.

我错误地认为object = new MyCustomObject()会给对象一个新的指针地址吗？我想要新对象而不更改指针地址(是的,我将确保清理旧对象).

考虑以下代码,

#include "iostream"
#include "conio.h"

using namespace std;

class sample
{
      private:
              int i;
      public:
             sample(int ii=0) : i(ii){                         
                   cout<<"Constructing Object"<<endl; 
                   }

             ~sample() { cout<<"Destructing Object"<<endl; }

             void* operator new(size_t nSize, void* loc){
                   cout <<"Inside new"<<endl;
                   cout <<loc<<endl;
                   return loc;
                   }

             void operator delete(void* ptr){
                  cout <<"Inside delete"<<endl;
                  free(ptr);
                  }
};


int main()
{
    int intArr[2];
    sample* samplePtr = new(intArr) sample(5);
    cout <<samplePtr<<endl;

    delete samplePtr;  
//    samplePtr->sample::~sample();
    getch();
}

输出:

Inside New
0x22ff38
Constructing Object
0x22ff38
Destructing Object
Inside Delete …