相关疑难解决方法(0)

怎么if __name__ == "__main__":办？

# Threading example
import time, thread

def myfunction(string, sleeptime, lock, *args):
    while True:
        lock.acquire()
        time.sleep(sleeptime)
        lock.release()
        time.sleep(sleeptime)

if __name__ == "__main__":
    lock = thread.allocate_lock()
    thread.start_new_thread(myfunction, ("Thread #: 1", 2, lock))
    thread.start_new_thread(myfunction, ("Thread #: 2", 2, lock))

while True:
    reply = input('Enter text')
    if reply == 'stop': break
    print(reply.upper())

结果是:

Enter text:Traceback (most recent call last):
  File "C:\PythonProjects\5.py", line 2, in <module>
    reply = input('Enter text:')
EOFError: EOF when reading a line
[Finished in 0.2s with exit code 1]

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它只在Sublime Text 2.我试过IDLE,试过命令行,一切都很完美.为什么Subleme会对我大喊大叫？

顺便说一句,也许你也可以解释我在这种情况下可能意味着什么.当然,我在文档中已经读过,如果从输入中读取EOF,则会引发相应的错误.我想模仿这种情况.仅输入键盘？如果是,我应该输入什么组合键才能获得EOF？

先感谢您.