我试过下面的代码.我从其他一些帖子中获取了这段代码,这些帖子根据作者是正确的.但是当我尝试跑步时,它并没有给我确切的结果.
这主要是按顺序打印偶数和奇数值.
public class PrintEvenOddTester {
public static void main(String ... args){
Printer print = new Printer(false);
Thread t1 = new Thread(new TaskEvenOdd(print));
Thread t2 = new Thread(new TaskEvenOdd(print));
t1.start();
t2.start();
}
}
class TaskEvenOdd implements Runnable {
int number=1;
Printer print;
TaskEvenOdd(Printer print){
this.print = print;
}
@Override
public void run() {
System.out.println("Run method");
while(number<10){
if(number%2 == 0){
System.out.println("Number is :"+ number);
print.printEven(number);
number+=2;
}
else {
System.out.println("Number is :"+ number);
print.printOdd(number);
number+=2;
}
}
}
}
class Printer …奇数偶数打印使用thread.Create一个线程类,两个线程实例.一个将打印奇数,另一个将打印偶数.
我做了以下编码.但它涉及死锁状态.有人可以解释一下可能是什么原因吗？
public class NumberPrinter implements Runnable{
private String type;
private static boolean oddTurn=true;
public NumberPrinter(String type){
this.type=type;
}
public void run() {
int i=type.equals("odd")?1:2;
while(i<10){
if(type.equals("odd"))
printOdd(i);
if(type.equals("even"))
printEven(i);
i=i+2;
}
}
private synchronized void printOdd(int i){
while(!oddTurn){
try {
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.println(type + i);
oddTurn=false;
notifyAll();
}
private synchronized void printEven(int i){
while(oddTurn){
try {
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.println(type + i);
oddTurn=true;
notifyAll();
}
public …