相关疑难解决方法(0)

我有这个,但它不起作用:

$query = "ALTER TABLE `".$table_prefix."posts_to_bookmark` 
            ADD `ping_status` INT( 1 ) NOT NULL BEFORE `onlywire_status`";

我很感激!

CREATE TABLE Properties
(
    ID int AUTO_INCREMENT,
    language int,
    stonecolor int,
    gamefield int,
    UserID int,
    PRIMARY KEY(ID),
    FOREIGN KEY(language) REFERENCES Language(ID),
    FOREIGN KEY(stonecolor) REFERENCES StoneColor(ID),
    FOREIGN KEY(gamefield) REFERENCES GameField(ID)
) ENGINE = INNODB;

CREATE TABLE User
(
    ID int AUTO_INCREMENT,
    vorname varchar(30) NOT NULL,
    name varchar(30) NOT NULL,
    email varchar(40) NOT NULL,
    password varchar(40) NOT NULL,
    nickname varchar(15) NOT NULL,
    score int,
    isadmin int DEFAULT 0,
    gamesPlayed int,
    properties int NOT NULL,
    PRIMARY KEY(ID),
    UNIQUE (email),
    UNIQUE (nickname)

) ENGINE …

我试图在phpMyAdmin中向现有表添加多个列,但我一直收到同样的错误:

#1064 - 您的SQL语法有错误; 查看与MySQL服务器版本对应的手册,以获得正确的语法...

我在写信:

ALTER TABLE `WeatherCenter`
   ADD COLUMN
      BarometricPressure SMALLINT NOT NULL,
      CloudType VARCHAR(70) NOT NULL,
      WhenLikelyToRain VARCHAR(30) NOT NULL;

我已经在StackOverflow上提到了过去的帖子,我遵循专家的建议,为什么我会收到错误？

如何使用Alembic或SQLAlchemy将另一列之后的列添加到数据库？这相当于这个SQL子句:

ALTER TABLE foo
CHANGE COLUMN bar
bar COLUMN_DEFINITION_HERE
AFTER OTHER_COLUMN;
-- or
ALTER TABLE foo ADD COLUMN baz AFTER bar;

我也尝试了这个邮件列表线程中的建议,但它没有帮助.

虽然查询时顺序无关紧要,但在SQL shell中有助于大表的可读性.