如果故障安全迭代器创建一个单独的副本并对其进行处理,那么它如何知道对原始文件所做的任何更改?
public class concurrentHashMap {
public static void main(String[] args) throws InterruptedException {
MapCheck obj1 = new MapCheck();
Thread t1 = new Thread(new Runnable() {
@Override
public void run() {
obj1.put();
}
});
Thread t2 = new Thread(new Runnable() {
@Override
public void run() {
obj1.iterte();
}
});
t1.start();
t2.start();
t1.join();
t2.join();
}
}
class MapCheck {
Map<Integer,String> map = new ConcurrentHashMap<>();
{
map.put(1, "pujan");
map.put(2, "manish");
map.put(3, "swati");
}
void iterte() throws InterruptedException {
for (int key : map.keySet()) …Run Code Online (Sandbox Code Playgroud) 当满足特定条件时,我试图从两个 arrayList 中删除内容。但是当条件满足时,我得到并发修改错误。在互联网上搜索后,我看到了使用迭代器概念解决此问题的解决方案,但这也不起作用。
这是我尝试过的两个代码变体:[我的代码在 Kotlin 中]
第一种变化:删除后立即出错
var index = 0
for (snap: DataSnapshot in snaps){
if (snap.key == snapshot.key){
snaps.removeAt(index)
emailOfSenders.removeAt(index)
}
index++
}
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第二种变化:如果数组列表中的项目小于 3,则有效,但如果项目为 3 或大于 3,我会收到相同的错误
var index = 0
val iter: Iterator<DataSnapshot> = snaps.iterator()
while (iter.hasNext()) {
val snap: DataSnapshot = iter.next()
if (snap.key == snapshot.key){
snaps.removeAt(index)
emailOfSenders.removeAt(index)
}
index++
}
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错误日志:
2020-11-18 13:52:32.829 18935-18935/com.rofy.snapyandroid E/AndroidRuntime: FATAL EXCEPTION: main
Process: com.rofy.snapyandroid, PID: 18935
java.util.ConcurrentModificationException
at java.util.ArrayList$Itr.next(ArrayList.java:860)
at com.rofy.snapyandroid.SnapsActivity$onCreate$1.onChildRemoved(SnapsActivity.kt:54)
at com.google.firebase.database.core.ChildEventRegistration.fireEvent(ChildEventRegistration.java:88)
at com.google.firebase.database.core.view.DataEvent.fire(DataEvent.java:63)
at com.google.firebase.database.core.view.EventRaiser$1.run(EventRaiser.java:55)
at …Run Code Online (Sandbox Code Playgroud)