相关疑难解决方法(0)

尝试调用"persist"方法将实体模型保存到Spring MVC Web应用程序中的数据库时,我收到此错误.无法在互联网上找到任何与此特定错误相关的帖子或页面.似乎EntityManagerFactory bean出了问题,但我对Spring编程还是比较新的,所以对我来说似乎所有内容都已经初始化很好并且根据web中的各种教程文章.

调度员servlet.xml中

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc"
 xmlns:context="http://www.springframework.org/schema/context"
 xmlns:jpa="http://www.springframework.org/schema/data/jpa"
xsi:schemaLocation="
 http://www.springframework.org/schema/mvc 
 http://www.springframework.org/schema/mvc/spring-mvc-4.0.xsd
 http://www.springframework.org/schema/beans 
 http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
 http://www.springframework.org/schema/context 
  http://www.springframework.org/schema/context/spring-context-4.0.xsd
  http://www.springframework.org/schema/jdbc
  http://www.springframework.org/schema/jdbc/spring-jdbc-3.2.xsd
  http://www.springframework.org/schema/data/jpa
  http://www.springframework.org/schema/data/jpa/spring-jpa-1.3.xsd
  http://www.springframework.org/schema/data/repository
  http://www.springframework.org/schema/data/repository/spring-repository-1.5.xsd
  http://www.springframework.org/schema/jee
  http://www.springframework.org/schema/jee/spring-jee-3.2.xsd">

    <context:component-scan base-package="wymysl.Controllers" />
    <jpa:repositories base-package="wymysl.repositories"/> 
    <context:component-scan base-package="wymysl.beans" /> 
    <context:component-scan base-package="wymysl.Validators" /> 
    <bean
     class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" />
     <bean class="org.springframework.orm.hibernate4.HibernateExceptionTranslator"/>

     <bean id="passwordValidator" class="wymysl.Validators.PasswordValidator"></bean>

     <bean id="dataSource"
        class="org.springframework.jdbc.datasource.DriverManagerDataSource">

        <property name="driverClassName" value="oracle.jdbc.driver.OracleDriver" />
        <property name="url" value="jdbc:oracle:thin:@localhost:1521:xe" />
        <property name="username" value="system" />
        <property name="password" value="polskabieda1" />
    </bean>

 <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
    <property name="persistenceXmlLocation" value="classpath:./META-INF/persistence.xml" />
    <property name="dataSource" ref="dataSource" />

    <property …

我正在使用Spring/Spring-data-JPA,并发现自己需要在单元测试中手动强制提交.我的用例是我正在进行多线程测试,其中我必须使用在生成线程之前持久化的数据.

不幸的是,鉴于测试在一个@Transactional事务中运行,即使是一个flush也没有让它可以被生成的线程访问.

   @Transactional   
   public void testAddAttachment() throws Exception{
        final Contract c1 = contractDOD.getNewTransientContract(15);
        contractRepository.save(c1);

        // Need to commit the saveContract here, but don't know how!                
        em.getTransaction().commit();

        List<Thread> threads = new ArrayList<>();
        for( int i = 0; i < 5; i++){
            final int threadNumber = i; 
            Thread t =  new Thread( new Runnable() {
                @Override
                @Transactional
                public void run() {
                    try {
                        // do stuff here with c1

                        // sleep to ensure that the thread is not …

在下面的代码方法doService1()更新正确的SQL但doService2()sql有一些问题,但是当我调用doService()它必须提交doService1()更新到DB,即使doService2()有一个sql exception因为doService2() 有一个REQUIRES_NEW Propagation类型,但当我doService1()没有这个更新不提交数据库..

@Service public class DbClass {

      static Logger log = Logger.getLogger(
              DbClass.class.getName());

@Autowired
private DataSource dataSource;

@Transactional(propagation=Propagation.REQUIRED)
public void doService(){
    doService1();
    doService2();
}

@Transactional(propagation=Propagation.REQUIRED)
public void doService1(){
    JdbcTemplate jdbcTemplate = new JdbcTemplate(dataSource);
    String sql = "  update BATCHJOBSTATUS set PROCESSINGDATE = '20130322'  " ;
    int rowCount1 =  jdbcTemplate.update(sql);
    System.out.println(" rowCount1 >" + rowCount1);
}

@Transactional(propagation=Propagation.REQUIRES_NEW)
public void doService2(){
    JdbcTemplate jdbcTemplate …