这是一个非常简单的问题.请考虑以下代码:
#include <iostream>
#include <memory>
typedef std::unique_ptr<void> UniqueVoidPtr;
int main() {
UniqueVoidPtr p(new int);
return 0;
}
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使用以下命令使用cygwin(g ++ 4.5.3)进行编译g++ -std=c++0x -o prog file.cpp就可以了.但是,使用Microsoft编译器(VS 2010或2013)进行编译时出现此错误:
C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\memory(2067) : error C2070: 'void': illegal sizeof operand
C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\memory(2066) : while compiling class template member function 'void std::default_delete<_Ty>::operator ()(_Ty *) const'
with
[
_Ty=void
]
C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\type_traits(650) : see reference to class template instantiation 'std::default_delete<_Ty>' being compiled
with
[ …Run Code Online (Sandbox Code Playgroud) 我在C++类中有一个OpenGL对象.由于我正在使用RAII,我想让析构函数删除它.所以我的班级看起来像:
class BufferObject
{
private:
GLuint buff_;
public:
BufferObject()
{
glGenBuffers(1, &buff_);
}
~BufferObject()
{
glDeleteBuffers(1, &buff_);
}
//Other members.
};
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这看起来很有效.但是当我执行以下任何操作时,我在使用它时会开始出现各种OpenGL错误:
vector<BufferObject> bufVec;
{
BufferObject some_buffer;
//Initialize some_buffer;
bufVec.push_back(some_buffer);
}
bufVec.back(); //buffer doesn't work.
BufferObject InitBuffer()
{
BufferObject buff;
//Do stuff with `buff`
return buff;
}
auto buff = InitBuffer(); //Returned buffer doesn't work.
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这是怎么回事?
注意:这是尝试建立这些问题的规范答案.