相关疑难解决方法(0)

我只是在pastebin http://pastebin.com/KBtqrAkZ的 codeigniter控制器部分插入数据

  public function add_product()
  {
    $this->lang->load('log_in', 'english');
        log_in_check($this->lang->line('log_in_authentication_error'), 'admin/log_in');
        $this->lang->load('common', 'english');
        $data['title'] = $this->lang->line('admin_index_title');
        $this->load->view('admin_template/header', $data);
        $this->load->view('admin_template/left_menu');
    $data['error_msg'] = '';
        if ($this->form_validation->run('add_product') === TRUE)
        {
      $this->admin_model->add_product($this->input->post());
            $this->session->set_flashdata('status_msg', $this->lang->line('add_product_success'));
            redirect(uri_string(), 'refresh');
      exit ;
          $data['error_msg'] = $this->lang->line('add_product_invalid_data');
        }
        $this->load->view('admin/add_product');
        //$this->load->view('admin_template/notification');
        $this->load->view('admin_template/footer');  
  }

比我的模型部分简单添加在pastebin http://pastebin.com/WiLHV2sr

  public function add_product($data = array())
  {
    $this->db->insert('ishop_product', $data);
    return $this->db->insert_id();
  }

如果我按ctrl + F5或F5而不是数据插入,我的问题是重定向后.我是codeigniter的新手.请帮帮我.任何帮助将不胜感激.

我有一个表单,将数据传递给cc处理终端,以及编写PDF合同和收据.表单中内置了验证,我试图添加一个函数,在提供验证通过一次单击后禁用提交按钮.

我对帖子数据了解不多,但我想确定一下:

1. Still posts the data. 2. Still validates. 3. Does not allow the user to submit multiple times.

这是我的POST代码块:

<form method="POST" action="partner_register_ihg.php" onSubmit="javascript:return WebForm_OnSubmit();"  id="docContainer" autoeventwireup="true" enctype="multipart/form-data" novalidate class="fb-toplabel fb-100-item-column fb-large selected-object" style="width: 800px;" data-form="preview">

这是我的提交部分

<input type="submit" name="subbutton" onClick='javascript:WebForm_DoPostBackWithOptions(new WebForm_PostBackOptions("subbutton", "", true, "", "", false, false))' id="subbutton" class="fb-button-special" value="Submit" />

这是我的验证码的一小部分

var RequiredFieldValidator30 = document.all ? document.all["RequiredFieldValidator30"] : document.getElementById("RequiredFieldValidator30");
RequiredFieldValidator30.controltovalidate = "item56_text_1";
RequiredFieldValidator30.errormessage = "Please enter the shipping zip code.";
RequiredFieldValidator30.display = "None";
RequiredFieldValidator30.evaluationfunction = "RequiredFieldValidatorEvaluateIsValid";
RequiredFieldValidator30.initialvalue …