相关疑难解决方法(0)

看来PHP对象是通过引用传递的.甚至赋值运算符似乎也没有创建Object的副本.

这是一个简单,人为的证明:

<?php

class A {
    public $b;
}


function set_b($obj) { $obj->b = "after"; }

$a = new A();
$a->b = "before";
$c = $a; //i would especially expect this to create a copy.

set_b($a);

print $a->b; //i would expect this to show 'before'
print $c->b; //i would ESPECIALLY expect this to show 'before'

?>

在两个印刷案例中,我都在"追求"

那么,我如何通过值传递$ a到set_b(),而不是通过引用？