相关疑难解决方法(0)

我试图将基于xml的Spring MVC应用程序移动到基于Java配置的应用程序.似乎与maven中可用的各种java.servlet类不匹配.例如,有些提供addServlet()方法,有些则不提供.

这是我的配置类:

public class MyWebAppInitializer implements WebApplicationInitializer {
    @Override
    public void onStartup(ServletContext container) throws ServletException {

        AnnotationConfigWebApplicationContext rootContext =
                new AnnotationConfigWebApplicationContext();
        rootContext.register(JpaSandboxConf.class);

        ServletRegistration.Dynamic registration = container.addServlet("dispatcher", new DispatcherServlet());
        registration.setLoadOnStartup(1);
        registration.addMapping("/myapp/*");
    }
}

这似乎相当无可争议.为了得到

container.addServlet()

方法,我把它包括在我的pom中:

<dependency>
    <groupId>org.apache.tomcat</groupId>
    <artifactId>tomcat-servlet-api</artifactId>
    <version>7.0.30</version>
</dependency>

我试过这个,但是下面的条目中的ServletContext类没有工作(因为它没有提供addServlet()方法):

<dependency>
    <groupId>javax.servlet</groupId>
    <artifactId>com.springsource.javax.servlet</artifactId>
    <version>2.5.0</version>
    <scope>provided</scope>
</dependency>

当我尝试使用它时

mvn clean tomcat7:run

我不幸得到了

SEVERE: A child container failed during start
java.util.concurrent.ExecutionException: org.apache.catalina.LifecycleException: Failed to start component [StandardEngine[Tomcat].StandardHost[localhost].StandardContext[/]]
    at java.util.concurrent.FutureTask$Sync.innerGet(FutureTask.java:252)
    at java.util.concurrent.FutureTask.get(FutureTask.java:111)
    at org.apache.catalina.core.ContainerBase.startInternal(ContainerBase.java:1130)
    at org.apache.catalina.core.StandardHost.startInternal(StandardHost.java:782)
    at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:150)
    at org.apache.catalina.core.ContainerBase$StartChild.call(ContainerBase.java:1568)
    at …