在我的 json 模式中，我定义了这样的“颜色”
{
"colors": {
"type":"string",
"pattern": "AliceBlue|AntiqueWhite|Aqua|Aquamarine|Azure|Beige|Bisque|Black|BlanchedAlmond|Blue|BlueViolet|Brown|BurlyWood|CadetBlue|Chartreuse|Chocolate|Coral|CornflowerBlue|Cornsilk|Crimson|Cyan|DarkBlue|DarkCyan|DarkGoldenRod|DarkGray|DarkGrey|DarkGreen|DarkKhaki|DarkMagenta|DarkOliveGreen|DarkOrange|DarkOrchid|DarkRed|DarkSalmon|DarkSeaGreen|DarkSlateBlue|DarkSlateGray|DarkSlateGrey|DarkTurquoise|DarkViolet|DeepPink|DeepSkyBlue|DimGray|DimGrey|DodgerBlue|FireBrick|FloralWhite|ForestGreen|Fuchsia|Gainsboro|GhostWhite|Gold|Gray|Grey|Green|GreenYellow|HoneyDew|HotPink|IndianRed|Indigo|Ivory|Khaki|Lavender|LavenderBlush|LawnGreen|LemonChiffon|LightBlue|LightCoral|LightCyan|LightGoldenRodYellow|LightGray|LightGrey|LightGreen|LightPink|LightSalmon|LightSeaGreen|LightSkyBlue|LightSlateGray|LightSlateGrey|LightSteelBlue|LightYellow|Lime|LimeGreen|Linen|Magenta|Maroon|MediumAquaMarine|MediumBlue|MediumOrchid|MediumPurple|MediumSeaGreen|MediumSlateBlue|MediumSpringGreen|MediumTurquoise|MediumVioletRed|MidnightBlue|MintCream|MistyRose|Moccasin|NavajoWhite|Navy|OldLace|Olive|OliveDrab|Orange|OrangeRed|Orchid|PaleGoldenRod|PaleGreen|PaleTurquoise|PaleVioletRed|PapayaWhip|PeachPuff|Peru|Pink|Plum|PowderBlue|Purple|RebeccaPurple|Red|RosyBrown|RoyalBlue|SaddleBrown|Salmon|SandyBrown|SeaGreen|SeaShell|Sienna|Silver|SkyBlue|SlateBlue|SlateGray|SlateGrey|Snow|SpringGreen|SteelBlue|Tan|Teal|Thistle|Tomato|Turquoise|Violet|Wheat|White|WhiteSmoke|Yellow|YellowGreen"
}
}
我怎样才能让这个模式不区分大小写？
谢谢
我正在尝试使用单个JSON文件来验证前端(JS)和后端(PHP)的数据.我无法弄清楚如何在json字符串中使用我的模式,PHP不会转换它.这是我想要使用的(电子邮件验证):
'{"name":"email", "pattern":"^[a-z0-9]+(\.[_a-z0-9]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,15})$"}'
我想模式中的某些内容不会被视为字符串？实际上,它不会转换为PHP中的对象.我不应该逃避任何事情,但我可能错了......
谢谢
编辑:按照评论中的建议尝试:
json_decode('{"name":"email", "pattern":"^[a-z0-9]+(\\.[_a-z0-9]+)*@[a-z0-9-]+(\\.[a-z0-9-]+)*(\\.[a-z]{2,15})$"}??'); ==> NULL