我正在尝试在C中制作一个简单的斐波那契计算器,但在编译时gcc告诉我,我错过了战俘和地板功能.怎么了?
码:
#include <stdio.h>
#include <math.h>
int fibo(int n);
int main() {
printf("Fib(4) = %d", fibo(4));
return 0;
}
int fibo(int n) {
double phi = 1.61803399;
return (int)(floor((float)(pow(phi, n) / sqrt(5)) + .5f));
}
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输出:
gab@testvm:~/work/c/fibo$ gcc fib.c -o fibo
/tmp/ccNSjm4q.o: In function `fibo':
fib.c:(.text+0x4a): undefined reference to `pow'
fib.c:(.text+0x68): undefined reference to `floor'
collect2: ld returned 1 exit status
Run Code Online (Sandbox Code Playgroud) 我尝试在C中编译一个需要"math.h"的库,这里是.c文件的开头:
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <time.h>
#include "sparse_matrix.h"
...
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我用这个命令编译:
gcc -c ./sparse_matrix.c -o sparse_matrix.o -lm -Wall -pedantic -std=c99 -g -O
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但即使文件后面的#include完成和标志-lm(我已尝试在行尾但没有改变)我仍然得到错误:
undefined reference to « sqrt »
collect2: error: ld returned 1 exit status
谷歌搜索一小时后,我没有得到它.我在ubuntu 14.10(utopic unicorn)下使用gcc 4.9.提前感谢您的帮助!
当试图调用函数时math.h,我收到如下链接错误
undefined reference to sqrt
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但我正在做一个#include <math.h>
我正在使用gcc并编译如下:
gcc -Wall -D_GNU_SOURCE blah.c -o blah
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为什么链接器找不到定义sqrt?
I am trying to run the following test program on my Solaris 10 sparc machine using gcc 5.5.0
#include <iostream>
#include <cmath>
int main()
{
std::cout << "exp2(4) = " << std::exp2(4) << '\n'
<< "exp2(0.5) = " << std::exp2(0.5) << '\n'
<< "exp2(-4) = " << std::exp2(-4) << '\n';
return 0;
}
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Here are the OS details,
~$ uname -a
SunOS sovms577 5.10 Generic_147147-26 sun4v sparc SUNW,SPARC-Enterprise-T5220
~$ cat /etc/release
Oracle Solaris 10 1/13 s10s_u11wos_24a SPARC
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