相关疑难解决方法(0)

我正在学习Java中的死锁,并且有来自Sun官方教程的示例代码:

阿方斯和加斯顿是朋友,也很有礼貌的信徒.严格的礼貌规则是,当你向朋友鞠躬时,你必须保持鞠躬,直到你的朋友有机会归还弓箭.不幸的是,这条规则没有考虑到两个朋友可能同时互相鞠躬的可能性.

public class Deadlock {
    static class Friend {
        private final String name;
        public Friend(String name) {
            this.name = name;
        }
        public String getName() {
            return this.name;
        }
        public synchronized void bow(Friend bower) {
            System.out.format("%s: %s has bowed to me!%n", 
                    this.name, bower.getName());
            bower.bowBack(this);
        }
        public synchronized void bowBack(Friend bower) {
            System.out.format("%s: %s has bowed back to me!%n",
                    this.name, bower.getName());
        }
    }

    public static void main(String[] args) {
        final Friend alphonse = new Friend("Alphonse");
        final Friend gaston = new Friend("Gaston"); …