相关疑难解决方法(0)

我想用twitter bootstrap创建工具提示或弹出窗口.据我所知,没有建立方式来做到这一点.

$('#selector').popover({
  placement: 'bottom'
});

例如,假设我想将创建的工具提示向上移动5px并从其计算位置离开5px.有关最佳方法的任何想法吗？

这就是我想做的事情:

$('#selector').popover({
  placement: 'bottom',
  callback: function(){
    alert('Awesome');
  }
});

我有一个位于弹出框内的日期选择器.Datepicker无法正常工作.有没有人这样做过

<div class="col-sm-4">
            <button tabindex="0" class="btn btn-primary" role="button" data-toggle="popover" data-trigger="click" 
                data-placement="bottom" data-container="body" data-html="true" id="login"><i class="fa fa-calendar"></i> - <i class="fa fa-calendar"></i>
            </button>
             <div id="popover-content" class="hide">
                <form role="form" method="post">
                    <div class="form-group">
                        <label>Start time?</label>
                        <div class='input-group date' id='datetimepicker1'>
                            <input type='text' class="form-control" placeholder="Start Date time of event"/>
                            <span class="input-group-addon">
                                <span class="glyphicon glyphicon-calendar"></span>
                            </span>
                        </div>
                    </div>
                    <div class="form-group">
                        <label>End time?</label>
                        <div class='input-group date' id='datetimepicker2'>
                            <input type='text' class="form-control" placeholder="End Date time"/>
                            <span class="input-group-addon">
                                <span class="glyphicon glyphicon-calendar"></span>
                            </span>
                        </div>
                    </div>
                    <div class="form-group">
                        <button class="btn btn-primary btn-block">Search between …