相关疑难解决方法(0)

我有2张桌子:

Table_1
[Group No] [Test No] [Description]
123        1         [First Test]
123        2         [Second Test]
123        3         [Third Test]

Table_2
[Sample No] [Test No] [Result Description]
ABC         1         [Some More Result]
ABC         3         [Some Result]
DEF         1         [A Result]
DEF         2         [Results More]
DEF         3         [Bad Results]

这是我的查询:

SELECT Table_1.[Group No], Table_1.[Test No], Table_1.Description, Table_2.[Result Description]
FROM Table_1 
LEFT OUTER JOIN Table_2 ON Table_1.[Test No] = Table_2.[Test No]
WHERE (Table_1.[Group No] = '123') AND (Table_2.[Sample No] = 'ABC')

djacobson的查询:

SELECT …