有没有办法编写以下函数,以便我的IDE不会抱怨该列是未使用的变量?
def get_selected_index(self):
(path, column) = self._tree_view.get_cursor()
return path[0]
Run Code Online (Sandbox Code Playgroud)
在这种情况下,我不关心元组中的第二项,只是想在解压缩时丢弃对它的引用.
我正在尝试连接以使用下面的脚本通过结构连接到亚马逊EC2.但我遇到了一个问题,我不知道如何解决它.
import os
from fabric.api import run, env, local, cd
WORK = os.getenv('HOME') + '/Work/myproject/'
env.user = 'ubuntu'
env.hosts = [
'128.248.268.288'
]
env.key_filename = [
'%s/aws/myproject.pem' % WORK
]
def deploy():
print("Executing on %(host)s as %(user)s" % env)
with cd('/sites/myproject.com/code/'):
run('ls')
Run Code Online (Sandbox Code Playgroud)
这是追溯.我不知道如何解决这个问题.
Traceback (most recent call last):
File "/Library/Python/2.6/site-packages/fabric/main.py", line 540, in main
commands[name](*args, **kwargs)
File "/Users/mickeyckm/Work/myproject/codes/giivee/fabfile.py", line 18, in deploy
run('ls')
File "/Library/Python/2.6/site-packages/fabric/network.py", line 391, in host_prompting_wrapper
return func(*args, **kwargs)
File "/Library/Python/2.6/site-packages/fabric/operations.py", line 422, in run
channel = …Run Code Online (Sandbox Code Playgroud)