相关疑难解决方法(0)

所以我使用navigator.geolocation.getCurrentPosition jammy有一个相当简单的JS.

$(document).ready(function(){
  $("#business-locate, #people-locate").click(function() {
    navigator.geolocation.getCurrentPosition(foundLocation, noLocation);
  });

  navigator.geolocation.getCurrentPosition(foundLocation, noLocation);

  function foundLocation(position) {
    var lat = position.coords.latitude;
    var lon = position.coords.longitude;
    var userLocation = lat + ', ' + lon;
    $("#business-current-location, #people-current-location").remove();
    $("#Near-Me")
      .watermark("Current Location")
      .after("<input type='hidden' name='business-current-location' id='business-current-location' value='"+userLocation+"' />");
    $("#people-Near-Me")
      .watermark("Current Location")
      .after("<input type='hidden' name='people-current-location' id='people-current-location' value='"+userLocation+"' />");
  }
  function noLocation() {
    $("#Near-Me").watermark("Could not find location");
    $("#people-Near-Me").watermark("Could not find location");
  }
})//end DocReady

基本上这里发生的是我们得到当前位置,如果得到的话,两个"水印"被放置在两个字段中,表示"当前位置",两个隐藏字段用lat-long数据作为它们的值(它们被删除)在一开始所以他们不会每次都重复).还有两个按钮,它们具有与之相关的点击功能,可以执行相同的操作.不幸的是,每三次左右,它都有效.这有什么问题???

我正在寻找一个javascript函数或jquery库来将地理位置代码(例如42.2342,32.23452)转换为街道地址

举些例子.

    navigator.geolocation.getCurrentPosition(
      function(pos) {
        $("#lat_field").val(pos.coords.latitude);
        $("#long_field").val(pos.coords.longitude);
      }
    );

这是一个获取地址数据的google api网址

http://maps.googleapis.com/maps/api/geocode/json?latlng=41.03531125,29.0124264&sensor=false

我想看看"formatted_address":"HacıHesnaHatun Mh.,PaşaLimanıCd2-26,34674 Istanbul,Türkiye",

    navigator.geolocation.getCurrentPosition(
      function(pos) {
        $("#lat_field").val(pos.coords.latitude);
        $("#long_field").val(pos.coords.longitude);
        $("#adress_data").getaddrfromlatlong(pos.coords.latitude,pos.coords.longitude)
      }
    );

这个功能应该如何？``getaddrfromlatlong()