相关疑难解决方法(0)

我正在实现一个MVC4 + WebAPI版本的BluImp jQuery文件上传一切都适用于我最初的尝试,但我试图确保在下载非常大的文件(~2GB)时最好地使用内存.

我已经阅读了Filip Woj关于PushStreamContent的文章并尽可能地实现它(删除异步部分 - 也许这就是问题？).当我运行测试并观察TaskManager时,我没有看到明显不同的内存使用情况,我试图理解响应如何处理之间的差异.

这是我的StreamContent版本:

private HttpResponseMessage DownloadContentNonChunked()
{
    var filename = HttpContext.Current.Request["f"];
    var filePath = _storageRoot + filename;
    if (File.Exists(filePath))
    {
        HttpResponseMessage response = new HttpResponseMessage(HttpStatusCode.OK);
        response.Content = new StreamContent(new FileStream(filePath, FileMode.Open, FileAccess.Read));
        response.Content.Headers.ContentType = new MediaTypeHeaderValue("application/octet-stream");
        response.Content.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment")
        {
            FileName = filename
        };
        return response;
    }
    return ControllerContext.Request.CreateErrorResponse(HttpStatusCode.NotFound, "");
}

这是我的PushStreamContent版本:

public class FileDownloadStream
{
    private readonly string _filename;

    public FileDownloadStream(string filePath)
    {
        _filename = filePath;
    }

    public …

我有以下angularjs代码:

$scope.search = function() {
    creatorService.search($scope.model).then(function(data) {
        saveAs(new Blob([data], { type: "application/octet-stream'" }), 'testfile.zip');
    });
};

(也使用fileSaver.js)

然后在我的webapi2方面采用以下方法:

public HttpResponseMessage Post(Object parameters)
    {
        var streamContent = new PushStreamContent((outputStream, httpContext, transportContent) =>
           {
               try
               {
                   using (var zip = new ZipFile())
                   {
                       zip.AddEntry("test.txt", "test data");
                       zip.Save(outputStream);
                   }
               }
               finally
               {
                   outputStream.Close();
               }
           });
        streamContent.Headers.ContentType = new MediaTypeHeaderValue("application/zip");
        streamContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment")
        {
            FileName = "test.zip"
        };

        var response = new HttpResponseMessage(HttpStatusCode.OK)
        {
            Content = streamContent
        };

        return response;
    } …