我们在Spring 3.0中使用RestTemplate与xml配置,它工作得非常好.
<bean id="httpClient" class="org.apache.commons.httpclient.HttpClient">
<!-- <constructor-arg ref="httpClientParams"/> -->
</bean>
<bean id="httpClientFactory" class="org.springframework.http.client.CommonsClientHttpRequestFactory">
<constructor-arg ref="httpClient"/>
</bean>
<bean id="restTemplate" name="restTemplate" class="org.springframework.web.client.RestTemplate" autowire-candidate="true">
<constructor-arg ref="httpClientFactory" />
<property name="messageConverters">
<list>
<bean class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter">
</bean>
<bean class="org.springframework.http.converter.FormHttpMessageConverter"/>
<bean class="org.springframework.http.converter.StringHttpMessageConverter" />
</list>
</property>
</bean>
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但是,当我们尝试迁移到Spring 3.1时,不推荐使用CommonsClientHttpRequestFactory类,并且不再使用公共HttpClient.
我试图使用HttpComponentsClientHttpRequestFactory类和Apache HttpClient设置类似的配置,但没有得到如何设置凭据提供程序.
我们希望httpclient具有基本身份验证.有没有人这样做或任何指针将是很大的帮助.提前致谢.
java spring restful-authentication resttemplate apache-httpclient-4.x
这是我们的休息模板配置
@Bean
public RestTemplate infoBloxRestTemplate() {
RestTemplate restTemplate=new RestTemplate();
ArrayList<ClientHttpRequestInterceptor> interceptors = new ArrayList<>();
interceptors.add(httpBasicAuthenticationInterceptor());
restTemplate.setInterceptors(interceptors);
restTemplate.getMessageConverters().add(jacksonConverter());
restTemplate.setRequestFactory(genericHttpRequestFactory());
return restTemplate;
}
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我们正在尝试进行POST调用,该调用与Postman一起成功运行并返回正确的响应.
final HttpHeaders headers = new HttpHeaders();
headers.add("Accept", "application/json");
headers.add("Content-Type", "application/json");
HttpEntity<Object> httpEntity = new HttpEntity<Object>(record, headers);
StringBuilder uri = new StringBuilder(infobloxRestClient.createUrl("/record:host"));
infobloxRestClient.getRestTemplate().exchange(uri.toString(), HttpMethod.POST, httpEntity, String.class);
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但是这个POST调用失败并出现以下错误.这是我的堆栈跟踪:
com.sun.xml.ws.server.sei.TieHandler createResponse
SEVERE: null
java.lang.UnsupportedOperationException
at java.util.Collections$UnmodifiableCollection.add(Unknown Source)
at org.springframework.http.HttpHeaders.add(HttpHeaders.java:558)
at com.test.externalinterfaces.HTTPBasicAuthenticationInterceptor.intercept(HTTPBasicAuthenticationInterceptor.java:30)
at org.springframework.http.client.InterceptingClientHttpRequest$RequestExecution.execute(InterceptingClientHttpRequest.java:81)
at org.springframework.http.client.InterceptingClientHttpRequest.executeInternal(InterceptingClientHttpRequest.java:67)
at org.springframework.http.client.AbstractBufferingClientHttpRequest.executeInternal(AbstractBufferingClientHttpRequest.java:46)
at org.springframework.http.client.AbstractClientHttpRequest.execute(AbstractClientHttpRequest.java:49)
at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:488)
at org.springframework.web.client.RestTemplate.execute(RestTemplate.java:452)
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在这方面的任何帮助将非常有帮助.
如何使用Apache httpclient 4.3.2从Spring 4.0.3.RELEASE配置RestTemplate?我跟着代码SO 这里,并在这里,甚至可以从Apache的这里,似乎很简单,但它从来没有为我工作.我可以验证在使用curl和postman时是否正确发送了Authorization标头,但是从未使用以下代码发送Authorization标头:
public RestTemplate createBasicAuthTemplate(String username, String password) {
BasicCredentialsProvider credentialsProvider = new BasicCredentialsProvider();
credentialsProvider.setCredentials(AuthScope.ANY, new UsernamePasswordCredentials(username, password));
HttpClient httpClient = HttpClientBuilder.create()
.setDefaultCredentialsProvider(credentialsProvider)
.build();
ClientHttpRequestFactory requestFactory = new HttpComponentsClientHttpRequestFactory(httpClient);
RestTemplate template = new RestTemplate(requestFactory);
return template;
}
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并且代码被调用如下:
RestTemplate basicAuth = createBasicAuthTemplate("user@app.com", "password");
ResponseEntity<String> response = basicAuth.getForEntity(url, String.class);
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所以问题是:如何使用Apache httpclient 4.3.2从Spring 4.0.3.RELEASE配置RestTemplate?还有其他部分缺少上述代码吗?在上面的代码中是使用正确方法的RestTemplate吗?