我怎样才能让我的船发射多次射击？

Question

好的,我正在为学校做这个项目.我应该做一个太空入侵者类型的游戏.我已经完成了让我的船移动并开枪的机会.现在这就是问题所在,当我尝试多次射击时,它会擦除​​之前发射的子弹,然后发射一个根本不是一个好网站的新子弹.我怎样才能让它实际射击多次？

while (running == 1):
    screen.fill(white)
    for event in pygame.event.get():
        if (event.type == pygame.QUIT):
            running = 0
        elif (event.type == pygame.KEYDOWN):
            if (event.key == pygame.K_d):
                dir = "R"
                move = True
            elif (event.key == pygame.K_a):
                dir = "L"
                move = True
            elif (event.key == pygame.K_s):
                dir = "D"
                move = True
            elif (event.key == pygame.K_w):
                dir = "U"
                move = True
            elif (event.key == pygame.K_ESCAPE): 
                sys.exit(0)
            elif (event.key == pygame.K_SPACE):
                shot=True
                xbul=xgun + 18
                ybul=ygun
            #if key[K_SPACE]:
                #shot = True
        if (event.type == pygame.KEYUP):
            move = False

    #OBJECT'S MOVEMENTS
    if ((dir == "R" and xgun<460) and (move == True)):
        xgun = xgun + 5
        pygame.event.wait
    elif ((dir == "L" and xgun>0) and (move == True)):
        xgun = xgun - 5
        pygame.event.wait
    elif ((dir == "D" and ygun<660) and (move == True)):
        ygun = ygun + 5
        pygame.event.wait
    elif ((dir == "U" and ygun>0) and (move == True)):
        ygun = ygun - 5

    screen.blit(gun, (xgun,ygun))

    #PROJECTILE MOTION
    #key = pygame.key.get_pressed()

    if shot == True:
        ybul = ybul - 10
        screen.blit(bullet, (xbul, ybul))

    if xbul>640:
        shot=False

    pygame.display.flip()
    time.sleep(0.012)

Answer 1

你只有一个子弹的变量 - xbul和ybul.如果你想要多个项目符号,那么你应该将每个项目符号列为一个列表.您可以附加到每个列表以添加新项目符号,弹出以删除旧项目符号,并在绘制时迭代列表.