MySQL Query Join从两个表中选择不匹配的行

Question

我有两张桌子如下.

---

user_id   |   username        |  first_name |   role_type
-----------------------------------------------------------
1         |   testuser1       |  testu1     |    student
2         |   testuser2       |  testu2     |    student
3         |   testuser3       |  testu3     |    student
4         |   testuser4       |  testu4     |    student
5         |   testuser5       |  testu5     |    student
6         |   testuser6       |  testu6     |    admin
7         |   testuser7       |  testu7     |    admin
-----------------------------------------------------------

---

user_id   |   username         |    approved_id
----------------------------------------------------------------------
1         |   testuser1        |  3B888F52-50BC-11E2-B08B-99E5B2CADDF7
2         |   testuser2        |  3B888F52-50BC-11E2-B08B-99E5B2CADDF7
3         |   testuser3        |  3B888F52-50BC-11E2-B08B-99E5B2CADDF7
----------------------------------------------------------------------

我试过了这个问题

SELECT users.* FROM users 
WHERE users.username NOT IN(
     SELECT users_approval.username FROM users_approval 
     WHERE users_approval.approved_id = "3B888F52-50BC-11E2-B08B-99E5B2CADDF7"
) AND users.role_type = "student"

并得到以下结果

---

user_id   |   username        |  first_name |   role_type
-------------------------------------------------------------
4         |   testuser4       |  testu4     |    student
5         |   testuser5       |  testu5     |    student
-------------------------------------------------------------

有没有办法使用JOIN来获取与上面相同的结果集？

帮助很多.

Answer 1

SELECT users.* 
FROM   users 
       LEFT JOIN users_approval b
          ON users.username = b.username AND
             b.approved_id = "3B888F52-50BC-11E2-B08B-99E5B2CADDF7"
WHERE  users.role_type = "student" AND
       b.approved_id IS NULL

• SQLFiddle演示