使用电子邮件而不是用户名进行Symfony2身份验证/登录

Question

我一直在尝试使用Symfony2创建一个登录表单,用户可以使用他们的电子邮件地址和密码登录.我遇到了很多问题,最后意识到只有$username在我的AdminUser实体类中有一个属性才会有效.我试图在可能的情况下使用电子邮件而不是用户名,所以有人可以解释为什么$username需要或我出错的地方？此外,在我的login.html.twig文件中我仍在使用_username而不是_email如果这有什么区别？我的代码如下(我删除了一些不适用的getter和setter):

管理员实体:

namespace XXX\WebsiteBundle\Entity;

use Symfony\Component\Security\Core\User\UserInterface;
use Doctrine\ORM\Mapping as ORM;

/**
* AdminUser
*
* @ORM\Table(name="admin_user",indexes={@ORM\Index(name="indexes", columns={"deleted"})})
* @ORM\Entity
* @ORM\HasLifecycleCallbacks()
*/
class AdminUser implements UserInterface
{
/**
 * @var integer
 *
 * @ORM\Column(name="id", type="integer")
 * @ORM\Id
 * @ORM\GeneratedValue(strategy="AUTO")
 */
private $id;

/**
 * @var string
 *
 * @ORM\Column(name="name", type="string", length=45)
 */
private $name;

/**
 * @var string
 *
 * @ORM\Column(name="email", type="string", length=45, unique=true)
 */
private $email;

/**
 * @var string
 *
 * @ORM\Column(name="salt", type="string", length=255)
 */
private $salt;

/**
 * @var string
 *
 * @ORM\Column(name="password", type="string", length=255)
 */
private $password;

/**
 * @var integer
 *
 * @ORM\Column(name="enabled", type="integer", options={"default" = 0})
 */
private $enabled;

/**
 * @var string[] $roles
 *
 * @ORM\Column(name="roles", type="array")
 */
private $roles = array();

private $username;


/**
 * Gets the username.
 *
 * @return string The username.
 */
public function getUsername()
{
    return $this->email;
}

/**
 * Erases the user credentials.
 */
public function eraseCredentials()
{

}


/**
 * Returns the roles granted to the user.
 *
 * <code>
 * public function getRoles()
 * {
 *     return array('ROLE_USER');
 * }
 * </code>
 *
 * Alternatively, the roles might be stored on a ``roles`` property,
 * and populated in any number of different ways when the user object
 * is created.
 *
 * @return Role[] The user roles
 */
public function getRoles() {
    return $this -> roles;
}

/**
 * Set the roles of the user
 *
 * @var string[] $roles
 *
 * @return \XXX\WebsiteBundle\Entity\User this
 */
public function setRoles(array $roles) {
    $this -> roles = $roles;

    return $this;
}



} 

我的security.yml档案是:

jms_security_extra:secure_all_services:false表达式:true

security:
encoders:
    XXX\WebsiteBundle\Entity\AdminUser: sha512

role_hierarchy:
    ROLE_ADMIN:       ROLE_USER
    ROLE_SUPER_ADMIN: [ROLE_USER, ROLE_ADMIN, ROLE_ALLOWED_TO_SWITCH]

providers:
    main_provider:
        entity: { class: XXX\WebsiteBundle\Entity\AdminUser, property: email }

firewalls:
    dev:
        pattern:  ^/(_(profiler|wdt)|css|images|js)/
        security: false

    admin_firewall:
        pattern:  ^/admin.*
        anonymous: ~
        form_login:
            login_path:  /admin/login
            check_path:  /admin/login_check

access_control:
    - { path: ^/admin/login.*, roles: IS_AUTHENTICATED_ANONYMOUSLY }
    - { path: ^/admin.*, roles: ROLE_ADMIN } 

Answer 1

我想你应该用电子邮件更改属性,你也可以用你想要的任何东西改变_username参数:

entity:
            entity:
                class:               SecurityBundle:User
                property:            username

和

firewalls
    form_login:
        username_parameter: _username

您可能应该查看安全配置文档

Answer 2

这有点黑客，但您可以从注册表中删除用户名字段，并在您的用户实体中执行以下操作：

public function setEmail($email) 
{
    $this->email = $email;
    $this->username = $email;
}