使用Youtube API V3和PHP将视频上传到Youtube

Question

我正在尝试使用PHP将视频上传到Youtube.我正在使用Youtube API v3,我正在使用最新检出的Google API PHP客户端库源代码.
我使用
https://code.google.com/p/google-api-php-client/上提供的示例代码来执行身份验证.身份验证很顺利,但是当我尝试上传视频时,我得到Google_ServiceException的错误代码为500,消息为null.

我看了之前提到的以下问题: 使用php客户端库v3将视频上传到youtube但是接受的答案没有描述如何指定要上传的文件数据.
我发现了另一个类似的问题使用Youtube API v3和PHP上传文件,其中在评论中提到categoryId是必需的,因此我尝试在片段中设置categoryId,但它仍然提供相同的异常.

我还提到了文档站点上的Python代码(https://developers.google.com/youtube/v3/docs/videos/insert),但我在客户端库中找不到函数next_chunk.但我试图在循环(在代码片段中提到)重试获取错误代码500,但在所有10次迭代中我得到相同的错误.

以下是我正在尝试的代码段:

$youTubeService = new Google_YoutubeService($client);
if ($client->getAccessToken()) {
    print "Successfully authenticated";
    $snippet = new Google_VideoSnippet();
    $snippet->setTitle = "My Demo title";
    $snippet->setDescription = "My Demo descrition";
    $snippet->setTags = array("tag1","tag2");
    $snippet->setCategoryId(23); // this was added later after refering to another question on stackoverflow

    $status = new Google_VideoStatus();
    $status->privacyStatus = "private";

    $video = new Google_Video();
    $video->setSnippet($snippet);
    $video->setStatus($status);

    $data = file_get_contents("video.mp4"); // This file is present in the same directory as the code
    $mediaUpload = new Google_MediaFileUpload("video/mp4",$data);
    $error = true;
    $i = 0;

    // I added this loop because on the sample python code on the documentation page
    // mentions we should retry if we get error codes 500,502,503,504
    $retryErrorCodes = array(500, 502, 503, 504);
    while($i < 10 && $error) {
        try{
            $ret = $youTubeService->videos->insert("status,snippet", 
                                                   $video, 
                                                   array("data" => $data));

            // tried the following as well, but even this returns error code 500,
            // $ret = $youTubeService->videos->insert("status,snippet", 
            //                                        $video, 
            //                                        array("mediaUpload" => $mediaUpload); 
            $error = false;
        } catch(Google_ServiceException $e) {
            print "Caught Google service Exception ".$e->getCode()
                  . " message is ".$e->getMessage();
            if(!in_array($e->getCode(), $retryErrorCodes)){
                break;
            }
            $i++;
        }
    }
    print "Return value is ".print_r($ret,true);

    // We're not done yet. Remember to update the cached access token.
    // Remember to replace $_SESSION with a real database or memcached.
    $_SESSION['token'] = $client->getAccessToken();
} else {
    $authUrl = $client->createAuthUrl();
    print "<a href='$authUrl'>Connect Me!</a>";
}

这是我做错了吗？

Answer 1

我能够使用以下代码使上传工作:

if($client->getAccessToken()) {
    $snippet = new Google_VideoSnippet();
    $snippet->setTitle("Test title");
    $snippet->setDescription("Test descrition");
    $snippet->setTags(array("tag1","tag2"));
    $snippet->setCategoryId("22");

    $status = new Google_VideoStatus();
    $status->privacyStatus = "private";

    $video = new Google_Video();
    $video->setSnippet($snippet);
    $video->setStatus($status);

    $error = true;
    $i = 0;

    try {
        $obj = $youTubeService->videos->insert("status,snippet", $video,
                                         array("data"=>file_get_contents("video.mp4"), 
                                        "mimeType" => "video/mp4"));
    } catch(Google_ServiceException $e) {
        print "Caught Google service Exception ".$e->getCode(). " message is ".$e->getMessage(). " <br>";
        print "Stack trace is ".$e->getTraceAsString();
    }
}