Cal*_*vin 3 mysql foreign-keys mysql-workbench mysql-error-1452
我已经使用了有关该主题的其他帖子,但是我没有运气。
这是我执行的代码:
UPDATE tblOrderItems SET `ItemID` = 0004 WHERE `OrderNum`= 203 AND `OrderItemID` = 26
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这是我的错误:
Error Code: 1452. Cannot add or update a child row: a foreign key constraint fails (`cai0066`.`tblOrderItems`, CONSTRAINT `ItemID` FOREIGN KEY (`ItemID`) REFERENCES `tblCatalogItems` (`ItemID`))
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笔记:
INSERT或UPDATE进入时就会发生tblOrderItems。tblCatalogItems 确实有一个ItemID的0004。看到:这个这是MySQL Workbench生成的create语句:
delimiter $$
CREATE TABLE `tblCatalogItems` (
`ItemID` varchar(10) NOT NULL DEFAULT '',
`ItemName` varchar(50) DEFAULT NULL,
`Wholesale` decimal(10,2) DEFAULT NULL,
`Cost5-10` decimal(10,2) DEFAULT NULL,
`Cost11-19` decimal(10,2) DEFAULT NULL,
`Cost20` decimal(10,2) DEFAULT NULL,
`Retail` decimal(10,2) DEFAULT NULL,
PRIMARY KEY (`ItemID`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1$$
delimiter $$
CREATE TABLE `tblItemCosts` (
`Cost` decimal(10,2) DEFAULT NULL,
`VendorID` int(11) NOT NULL,
`ItemID` varchar(10) NOT NULL,
KEY `VendorID_idx` (`VendorID`),
KEY `ItemID_idx` (`ItemID`),
CONSTRAINT `VendorID` FOREIGN KEY (`VendorID`) REFERENCES `tblVendors` (`VendorID`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB DEFAULT CHARSET=latin1$$
delimiter $$
CREATE TABLE `tblOrderItems` (
`OrderItemID` int(11) NOT NULL AUTO_INCREMENT,
`OrderNum` int(11) NOT NULL,
`PayPalTxnID` int(10) DEFAULT NULL,
`Description` varchar(225) DEFAULT NULL,
`Quantity` int(11) DEFAULT NULL,
`UnitPrice` decimal(10,2) DEFAULT NULL,
`ItemStatus` varchar(30) DEFAULT NULL,
`TrackingNumber` varchar(50) DEFAULT NULL,
`ShippingCost` decimal(10,2) DEFAULT NULL,
`ItemID` varchar(50) DEFAULT NULL,
`TotalPrice` decimal(10,2) DEFAULT NULL,
PRIMARY KEY (`OrderItemID`,`OrderNum`),
UNIQUE KEY `PayPalTxnID_UNIQUE` (`PayPalTxnID`),
KEY `PayPalTxnID_idx` (`PayPalTxnID`),
KEY `UnitPrice_idx` (`ItemID`),
KEY `OrderNum_idx` (`OrderNum`),
CONSTRAINT `ItemID` FOREIGN KEY (`ItemID`) REFERENCES `tblCatalogItems` (`ItemID`),
CONSTRAINT `OrderNum` FOREIGN KEY (`OrderNum`) REFERENCES `tblOrders` (`OrderNum`) ON DELETE CASCADE ON UPDATE CASCADE,
CONSTRAINT `UnitPrice` FOREIGN KEY (`ItemID`) REFERENCES `tblCatalogItems` (`ItemID`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB AUTO_INCREMENT=7678 DEFAULT CHARSET=latin1$$
delimiter $$
CREATE TABLE `tblOrderItemStatus` (
`OrderItemID` int(11) NOT NULL,
`OrderDate` varchar(12) DEFAULT NULL,
`DesignProofSent` varchar(12) DEFAULT NULL,
`SubmittedToProduction` varchar(12) DEFAULT NULL,
`InProduction` varchar(12) DEFAULT NULL,
`Shipped` varchar(12) DEFAULT NULL,
PRIMARY KEY (`OrderItemID`),
UNIQUE KEY `OrderItemID_UNIQUE` (`OrderItemID`),
KEY `OrderItemID_idx` (`OrderItemID`),
CONSTRAINT `OrderItemID` FOREIGN KEY (`OrderItemID`) REFERENCES `tblOrderItems` (`OrderItemID`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB DEFAULT CHARSET=latin1$$
delimiter $$
CREATE TABLE `tblOrders` (
`OrderNum` int(11) NOT NULL AUTO_INCREMENT,
`PayPalTxnID` int(10) DEFAULT NULL,
`OrderDate` varchar(50) DEFAULT NULL,
`OrderStatus` varchar(10) DEFAULT 'New',
`RushFlag` bit(1) DEFAULT b'0',
`ShipName` varchar(50) DEFAULT NULL,
`ShipEmail` varchar(100) DEFAULT NULL,
`ShipAddress1` varchar(50) DEFAULT NULL,
`ShipAddress2` varchar(50) DEFAULT NULL,
`ShipCity` varchar(50) DEFAULT NULL,
`ShipState` char(2) DEFAULT NULL,
`ShipZip` varchar(10) DEFAULT NULL,
`ShippingCharge` decimal(10,2) DEFAULT NULL,
`TotalCost` decimal(10,2) DEFAULT NULL,
PRIMARY KEY (`OrderNum`),
UNIQUE KEY `PayPalTxnID_UNIQUE` (`PayPalTxnID`)
) ENGINE=InnoDB AUTO_INCREMENT=346 DEFAULT CHARSET=latin1$$
delimiter $$
CREATE TABLE `tblVendors` (
`VendorID` int(11) NOT NULL,
`VendorName` varchar(50) DEFAULT NULL,
PRIMARY KEY (`VendorID`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1$$
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我在此相关文章中尝试了该建议,但没有结果。这是一个尚未实际使用的新数据库。我刚刚用假数据填充了它。任何想法将不胜感激。
有一个外键约束tblOrderItems,它ItemID需要引用ItemID中已经存在的tblCatalogItems。
CONSTRAINT `ItemID` FOREIGN KEY (`ItemID`) REFERENCES `tblCatalogItems` (`ItemID`),
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该消息仅表示您正在尝试使用= 0004 tblOrderItems来引用该项目,但该项目不存在。tblCatalogItemsItemID
由于ItemID是varchar,因此您可能想引用,0004否则4在转换为varchar之前可能先将其转换为int 。如果ItemID实际存在= 0004 的行,则可能是您的问题。
UPDATE tblOrderItems SET `ItemID` = '0004' WHERE `OrderNum`= 203 AND `OrderItemID` = 26
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