我想知道如果我们假设Filesize大于内存,你如何在Java中操作大文本文件.我搜索了该主题,它表明大多数人都推荐java.nio这样的任务.
不幸的是,我没有找到任何关于如何操作文件的文档.例如,读取每一行,修改它,写它.我尝试过类似的东西,但这不起作用:
FileChannel fileChannel = null;
try {
fileChannel = new RandomAccessFile(file, "rw").getChannel();
ByteBuffer buffer = ByteBuffer.allocate(256);
while (fileChannel.read(buffer) != -1) {
buffer.rewind();
buffer.flip();
String nextLine = buffer.asCharBuffer().toString();
if (replaceBackSlashes) {
nextLine = nextLine.replace("\\\\", "/");
}
if (!(removeEmptyLines && StringUtils.isEmpty(nextLine))) {
buffer.flip();
buffer.asCharBuffer().put(nextLine);
}
buffer.clear();
}
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
} finally {
if (fileChannel != null) {
try {
fileChannel.close();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
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那你有什么建议?String nextline也与我文件中的任何内容都不匹配.也许我需要设置编码?
逐行.像这样......
public static void main(String[] args) throws Exception {
File someFile = new File("someFile.txt");
File temp = File.createTempFile(someFile.getName(), null);
BufferedReader reader = null;
PrintStream writer = null;
try {
reader = new BufferedReader(new FileReader(someFile));
writer = new PrintStream(temp);
String line;
while ((line = reader.readLine())!=null) {
// manipulate line
writer.println(line);
}
}
finally {
if (writer!=null) writer.close();
if (reader!=null) reader.close();
}
if (!someFile.delete()) throw new Exception("Failed to remove " + someFile.getName());
if (!temp.renameTo(someFile)) throw new Exception("Failed to replace " + someFile.getName());
}
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