考虑以下:
DateTime = {'2007-01-01 00:00';'2007-02-01 00:00';'2007-03-01 00:00'};
Headers = {'Datetime','Data'};
Dat = [100,200,300];
Data = [DateTime,num2cell(Dat')];
Final = [Headers;Data];
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如何将"Final"中的数据写入制表符分隔的文本文件中.我知道如何在变量仅由数字输入组成时使用fopen,fprintf等,但我正努力解决这个问题.我试过了:
fid = fopen('C:\Documents\test.txt','wt');
fprintf(fid,'%s\t%s\n',Final{:});
fclose(fid);
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但是,这不会生成与matlab中生成的文本格式相同的文本文件.怎样才能解决这个问题?
该解决方案提供了我认为您需要的功能; 我希望有用的一些评论是正确的
DateTime = {'2007-01-01 00:00';'2007-02-01 00:00';'2007-03-01 00:00'};
Headers = {'Datetime','Data'};
Dat = [100,200,300];
% // In the way you used fprintf it expects just strings ('%s\t%s\n'),
% // therefore Data should be composed exclusively by them.
% // Numbers are converted to strings by using num2str
% // by using cellfun we iteratively convert every element of num2cell(Dat')
% // in strings, obtaining a cell
Data = [DateTime,cellfun(@num2str, num2cell(Dat'), 'UniformOutput' , false )];
Final = [Headers;Data];
fid = fopen('test.txt','wt');
% // this iterates fprintf on the cell rows, giving you the output
cellfun(@(x,y) fprintf(fid,'%s\t%s\n',x,y),Final(:,1),Final(:,2));
fclose(fid);
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结果
Datetime Data
2007-01-01 00:00 100
2007-02-01 00:00 200
2007-03-01 00:00 300
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编辑:(来自评论)在一个N列单元格的一般情况下,你可以简单地去一个for循环,例如
for i = 1 : size(Final,1)
fprintf(fid,'%s ', Final{i,:} );
fprintf(fid,'\n');
end
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(结果相同,但不取决于列数).