rspec数组应该如何包含？另一个阵列

Question

我试图测试一个数组是否包含另一个(rspec 2.11.0)

test_arr = [1, 3]

describe [1, 3, 7] do
  it { should include(1,3) }
  it { should eval("include(#{test_arr.join(',')})")}
  #failing
  it { should include(test_arr) }
end    

这是rspec spec/test.spec ..F的结果

Failures:

  1) 1 3 7 
     Failure/Error: it { should include(test_arr) }
       expected [1, 3, 7] to include [1, 3]
     # ./spec/test.spec:7:in `block (2 levels) in <top (required)>'

Finished in 0.00125 seconds
3 examples, 1 failure

Failed examples:

rspec ./spec/test.spec:7 # 1 3 7 

包含rspec mehod不接受数组参数,这是避免"eval"的更好方法吗？

• 资源
• 规格

Answer 1

只需使用splat(*)运算符,它将元素数组扩展为可以传递给方法的参数列表:

test_arr = [1, 3]

describe [1, 3, 7] do
  it { should include(*test_arr) }
end

Answer 2

如果要声明子集数组的顺序，则需要做更多的事情should include(..)，因为RSpec的include匹配器仅声明每个元素都显示在数组中的任何位置，而不是所有参数都按顺序显示。

我最终使用each_cons来验证子数组是否按顺序存在，如下所示：

describe [1, 3, 5, 7] do
  it 'includes [3,5] in order' do
    subject.each_cons(2).should include([3,5])
  end

  it 'does not include [3,1]' do
    subject.each_cons(2).should_not include([3,1])
  end
end