您可以简单地获取周数,并在奇数(甚至!)时执行您的操作,如果该日是星期一,例如:
$time=time();
$dayNo=strftime('%u', $time); #1=monday
$weekNo=strftime('%U', $time); #week number
if (($dayNo==1) && ($weekNo%2))
{
#do something on mondays, alternating weeks
}
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